Pertanyaan

Diketahui K sp Na 3 PO 4 = 2 , 7 × 1 0 − 11 . Tentukan kelarutan Na 3 PO 4 dalam air!

Diketahui $K_{sp} Na_{3} PO_{4} = 2, 7 \times 1 0^{- 11}$ . Tentukan kelarutan $Na_{3} PO_{4}$ dalam air! $\;\;\;$

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

Klaim

N. Agnia

Master Teacher

Mahasiswa/Alumni Institut Pertanian Bogor

Jawaban terverifikasi

Jawaban

kelarutan dalam air adalah .

kelarutan

dalam air adalah 10 to the power of negative sign 3 end exponent space bevelled mol over L

Pembahasan

Jadi, kelarutan dalam air adalah .

$Na subscript 3 P O subscript 4 yields 3 Na to the power of plus sign and P O subscript 4 to the power of 3 minus sign space space space space space s space space space space space space space space space space space space 3 s space space space space space space space space space s K subscript sp equals open square brackets Na to the power of plus sign close square brackets cubed open square brackets P O subscript 4 end subscript to the power of 3 minus sign close square brackets 2 comma 7 cross times 10 to the power of negative sign 11 end exponent equals left parenthesis 3 s right parenthesis cubed open parentheses s close parentheses 2 comma 7 cross times 10 to the power of negative sign 11 end exponent equals 27 s to the power of 4 s equals fourth root of fraction numerator 2 comma 7 cross times 10 to the power of negative sign 11 end exponent over denominator 27 end fraction end root s equals fourth root of fraction numerator 27 cross times 10 to the power of negative sign 12 end exponent over denominator 27 end fraction end root s equals 10 to the power of negative sign 3 end exponent space bevelled mol over L space$

Jadi, kelarutan dalam air adalah . space space space