Diketahui massa atom relatif (Ar) dari beberapa tom di bawah ini: H=1, O=16, N=14, C=12, S=32, Na=23, K=39, Ca=40, Cl=35,5 Tentukan berapa volume dari 22 gram CO2 jika diukur pada keadaan standar!

Pertanyaan

Diketahui massa atom relatif $({\mathrm A}_{\mathrm r})$ dari beberapa tom di bawah ini:

H=1, O=16, N=14, C=12, S=32, Na=23, K=39, Ca=40, Cl=35,5

Tentukan berapa volume dari 22 gram ${\mathbf{CO}}_{\mathbf2}$ jika diukur pada keadaan standar! $\;$

Pembahasan:

Menentukan mol $C O subscript bold 2$

$table attributes columnalign right center left columnspacing 0px end attributes row cell mol space C O subscript 2 end cell equals cell fraction numerator massa space C O subscript 2 over denominator M subscript r space C O subscript 2 end fraction end cell row cell mol space C O subscript 2 end cell equals cell fraction numerator massa space C O subscript 2 over denominator left curly bracket left parenthesis 1 cross times A subscript r space C right parenthesis plus left parenthesis 2 cross times A subscript r space O subscript 2 right parenthesis right curly bracket end fraction end cell row cell mol space C O subscript 2 end cell equals cell fraction numerator 22 space gram over denominator left curly bracket left parenthesis 1 cross times 12 space gram space mol to the power of negative sign 1 end exponent right parenthesis plus left parenthesis 2 cross times A subscript r space 16 space gram space mol to the power of negative sign 1 end exponent right parenthesis right curly bracket end fraction end cell row cell mol space C O subscript 2 end cell equals cell fraction numerator 22 space gram over denominator left parenthesis 12 space gram space mol to the power of negative sign 1 end exponent plus 32 space gram space mol to the power of negative sign 1 end exponent right parenthesis end fraction end cell row cell mol space C O subscript 2 end cell equals cell fraction numerator 22 space gram over denominator 44 space gram space mol to the power of negative sign 1 end exponent end fraction end cell row cell mol space C O subscript 2 end cell equals cell 0 comma 5 space mol end cell end table$

Menentukan Volume $C O subscript bold 2$

$table attributes columnalign right center left columnspacing 0px end attributes row blank blank V end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell C O end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell blank subscript 2 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank mol end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell C O end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell blank subscript 2 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cross times end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank V end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell blank subscript STP end cell end table V table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell C O end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell blank subscript 2 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 0 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank comma end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 5 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank mol end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cross times end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 22 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank comma end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 4 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank L end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank mol end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell blank to the power of negative sign 1 end exponent end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank V end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell C O end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell blank subscript 2 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 11 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank comma end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 2 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank L end table$

Jadi volume dari 22 gram $C O subscript bold 2$ jika diukur pada keadaan standar adalah 11,2 L. $space$

Jawaban terverifikasi

Dijawab oleh:

L. Avicenna

Mahasiswa/Alumni Institut Teknologi Bandung

Terakhir diupdate 06 Oktober 2021

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

Tapi Roboguru masih mau belajar. Menurut kamu pembahasan kali ini sudah membantu, belum?

Membantu

Kurang Membantu

Apakah pembahasan ini membantu?

Belum menemukan yang kamu cari?

Post pertanyaanmu ke Tanya Jawab, yuk

Mau Bertanya

Pertanyaan serupa

Diketahui: Ar:C=12gmol−1,N=14gmol−1,O=16gmol−1,S=32gmol−1,H=1gmol−1,Fe=56gmol−1 Tentukan massa dari 4,48 liter gas dinitrogen pentaoksida (STP)!

Roboguru

Jika diketahui Ar C = 12, O = 16, H = 1, N = 14, maka di antara pasangan senyawa berikut yang mempunyai massa yang sama adalah .... 1 liter gas CH4 dengan 1 liter gas O2 3,01×1023 molekul O2 ...

Roboguru

Sebanyak 2 mol H2O(ArH=1gmol−1,O=16gmol−1) tentukan: massa H2O! volume (STP)!

Roboguru

Hitung massa dari 11,2 liter SO3 (STP)!

Roboguru

Hitung massa dari 2,24 liter O3 (STP)!

Roboguru