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Diketahui massa 1 atom oksigen  gram, jika massa a...

Diketahui massa 1 atom oksigen begin mathsize 14px style 2 comma 70 space x space 10 to the power of negative sign 23 end exponent end style gram, jika massa atom C adalah begin mathsize 14px style 1 comma 99 space x space 10 to the power of negative sign 23 end exponent end style gram, maka massa alom relatif O (begin mathsize 14px style A subscript r space O end style) adalah .... begin mathsize 14px style gram space mol to the power of negative sign 1 end exponent end style 

  1. begin mathsize 14px style fraction numerator 2 comma 70 cross times 10 to the power of negative sign 23 end exponent over denominator 12 cross times 1 comma 99 cross times 10 to the power of negative sign 23 end exponent end fraction end style 

  2. begin mathsize 14px style fraction numerator 1 comma 99 cross times 10 to the power of negative sign 23 end exponent over denominator 1 over 12 cross times 2 comma 70 cross times 10 to the power of negative sign 23 end exponent end fraction end style 

  3. begin mathsize 14px style fraction numerator 2 comma 70 cross times 10 to the power of negative sign 23 end exponent over denominator 1 over 12 cross times 1 comma 99 cross times 10 to the power of negative sign 23 end exponent end fraction end style 

  4. begin mathsize 14px style fraction numerator 1 over 12 cross times 2 comma 70 cross times 10 to the power of negative sign 23 end exponent over denominator 1 comma 99 cross times 10 to the power of negative sign 23 end exponent end fraction end style 

  5. begin mathsize 14px style fraction numerator 1 over 12 cross times 1 comma 99 cross times 10 to the power of negative sign 23 end exponent over denominator 2 comma 70 cross times 10 to the power of negative sign 23 end exponent end fraction end style 

Jawaban:

Untuk mengetahui massa atom relatif suatu unsur jika dibandingkan dengan massa atom begin mathsize 14px style C minus sign 12 end style adalah dengan membandingkan massa 1 atom unsur tersebut dengan begin mathsize 14px style begin inline style 1 over 12 end style end style massa atom karbon, dapat dirumuskan sebagai berikut:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell A subscript r space X end cell equals cell fraction numerator massa space 1 space atom space X over denominator 1 over 12 space massa space atom space C minus sign 12 end fraction end cell row cell A subscript r space O end cell equals cell fraction numerator massa space 1 space atom space O over denominator 1 over 12 space massa space atom space C minus sign 12 end fraction end cell row blank equals cell fraction numerator 2 comma 70 cross times 10 to the power of negative sign 23 end exponent over denominator 1 over 12 cross times 1 comma 99 cross times 10 to the power of negative sign 23 end exponent end fraction end cell end table end style 

Jadi, jawaban yang benar adalah C.

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