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Pertanyaan

Diketahui maka nilai y saat x = 2 1 ​ adalah ….

Diketahui begin mathsize 14px style y equals tan invisible function application open parentheses 2 x minus 1 close parentheses end style maka nilai saat  adalah ….

  1. begin mathsize 14px style negative 2 end style

  2. begin mathsize 14px style negative 1 end style

  3. begin mathsize 14px style 0 end style

  4. begin mathsize 14px style 1 end style

  5. undefined  

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S. Dwi

Master Teacher

Jawaban terverifikasi

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Pembahasan

Turunan pertama: Turunan kedua: Misalkan: Maka, Sehingga nilai saat adalah : Maka, jawaban yang tepat adalah C.

Turunan pertama:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row y equals cell tan invisible function application open parentheses 2 x minus 1 close parentheses end cell row cell y to the power of apostrophe end cell equals cell sec squared invisible function application open parentheses 2 x minus 1 close parentheses end cell row cell y to the power of apostrophe end cell equals cell fraction numerator 1 over denominator cos squared invisible function application open parentheses 2 x minus 1 close parentheses end fraction end cell end table end style

Turunan kedua:

Misalkan:

begin mathsize 14px style u equals 1 left right double arrow u to the power of apostrophe equals 0 v equals cos squared invisible function application open parentheses 2 x minus 1 close parentheses left right double arrow v to the power of apostrophe equals negative 4 cos invisible function application open parentheses 2 x minus 1 close parentheses sin invisible function application open parentheses 2 x minus 1 close parentheses end style

Maka,

begin mathsize 14px style y to the power of apostrophe apostrophe end exponent equals fraction numerator u to the power of apostrophe v minus u v to the power of apostrophe over denominator v squared end fraction y to the power of apostrophe apostrophe end exponent equals fraction numerator 0 times cos squared invisible function application open parentheses 2 x minus 1 close parentheses minus 1 times negative 4 cos invisible function application open parentheses 2 x minus 1 close parentheses sin invisible function application open parentheses 2 x minus 1 close parentheses over denominator cos to the power of 4 invisible function application open parentheses 2 x minus 1 close parentheses end fraction y to the power of apostrophe apostrophe end exponent equals fraction numerator 4 cos invisible function application open parentheses 2 x minus 1 close parentheses sin invisible function application open parentheses 2 x minus 1 close parentheses over denominator cos to the power of 4 invisible function application open parentheses 2 x minus 1 close parentheses end fraction y to the power of apostrophe apostrophe end exponent equals fraction numerator 4 sin invisible function application open parentheses 2 x minus 1 close parentheses over denominator cos cubed invisible function application open parentheses 2 x minus 1 close parentheses end fraction y to the power of apostrophe apostrophe end exponent equals fraction numerator 4 tan invisible function application open parentheses 2 x minus 1 close parentheses over denominator cos squared invisible function application open parentheses 2 x minus 1 close parentheses end fraction end style 

Sehingga nilai begin mathsize 14px style y apostrophe apostrophe end style saat begin mathsize 14px style x equals 1 half end style adalah :

begin mathsize 14px style y to the power of apostrophe apostrophe end exponent equals fraction numerator 4 tan invisible function application open parentheses 2 open parentheses 1 half close parentheses minus 1 close parentheses over denominator cos squared invisible function application open parentheses 2 open parentheses 1 half close parentheses minus 1 close parentheses end fraction equals fraction numerator 4 tan invisible function application 0 over denominator cos invisible function application 0 end fraction equals fraction numerator 4 times 0 over denominator 1 end fraction equals 0 end style 

Maka, jawaban yang tepat adalah C.

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