Pertanyaan

Diketahui f: R→R dengan .Nilai dari f − 1 ( 3 ) = ....

Diketahui f: R→R dengan $begin mathsize 14px style f open parentheses x close parentheses equals fraction numerator 2 x minus 3 over denominator x plus 8 end fraction comma space x not equal to negative 8 end style$ . Nilai dari $f^{- 1} (3) = ....$

27
9
3
-9
-27

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Jawaban terverifikasi

Pembahasan

$begin mathsize 12px style Ingat colon space Jika space f open parentheses x close parentheses equals fraction numerator a x plus b over denominator c x plus d end fraction comma space maka space f to the power of negative 1 end exponent open parentheses x close parentheses equals fraction numerator negative d x plus b over denominator c x minus a end fraction Sehingga space invers space dari space f open parentheses x close parentheses equals fraction numerator 2 x minus 3 over denominator x plus 8 end fraction open parentheses rightwards arrow fraction numerator stack 2 with underbrace below with a below x stack stack negative 3 with underbrace below with b below over denominator stack 1 with underbrace below with c below x stack stack plus 8 with underbrace below with d below end fraction close parentheses space adalah space f to the power of negative 1 end exponent open parentheses x close parentheses equals fraction numerator negative 8 x minus 3 over denominator x minus 2 end fraction Oleh space karena space itu comma space nilai space dari space f to the power of negative 1 end exponent open parentheses 3 close parentheses equals fraction numerator negative 8 left parenthesis 3 right parenthesis minus 3 over denominator 3 minus 2 end fraction space space space space space space space space space space equals fraction numerator negative 24 minus 3 over denominator 1 end fraction space space space space space space space space space space equals negative 27 end style$