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Diketahui dan . Maka, nilai p yang memenuhi dari adalah ....

Diketahui begin mathsize 14px style straight g open parentheses straight x minus 2 close parentheses equals 3 minus 2 straight x end style dan begin mathsize 14px style open parentheses straight f ring operator straight g close parentheses open parentheses straight x close parentheses equals 6 minus 3 straight x end style. Maka, nilai yang memenuhi dari begin mathsize 14px style straight f open parentheses straight p close parentheses equals negative 3 end style adalah ....

  1. begin mathsize 14px style 11 over 3 end style

  2. begin mathsize 14px style 3 end style

  3. begin mathsize 14px style negative 3 end style

  4. undefined

  5. begin mathsize 14px style negative 11 over 3 end style

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S. Nur

Master Teacher

Jawaban terverifikasi

Jawaban

jawabannya adalah D.

jawabannya adalah D.

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Pembahasan

Pertama, kita cari . Sehingga Misalkan , maka Diketahui , maka Jadi, jawabannya adalah D.

Pertama, kita cari undefined.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight g open parentheses straight x minus 2 close parentheses end cell equals cell 3 minus 2 straight x end cell row blank equals cell negative 1 minus 2 straight x plus 4 end cell row blank equals cell negative 1 minus 2 open parentheses straight x minus 2 close parentheses end cell row cell straight g open parentheses straight x close parentheses end cell equals cell negative 1 minus 2 straight x end cell end table end style 

Sehingga

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses straight f ring operator straight g close parentheses open parentheses straight x close parentheses end cell equals cell 6 minus 3 straight x end cell row cell straight f open parentheses straight g open parentheses straight x close parentheses close parentheses end cell equals cell 6 minus 3 straight x end cell row cell straight f open parentheses negative 1 minus 2 straight x close parentheses end cell equals cell 6 minus 3 straight x end cell end table end style 

Misalkan begin mathsize 14px style negative 1 minus 2 straight x equals straight a rightwards arrow straight x equals fraction numerator straight a plus 1 over denominator negative 2 end fraction end style, maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight f open parentheses negative 1 minus 2 straight x close parentheses end cell equals cell 6 minus 3 straight x end cell row cell straight f open parentheses straight a close parentheses end cell equals cell 6 minus 3 open parentheses fraction numerator straight a plus 1 over denominator negative 2 end fraction close parentheses end cell row cell straight f open parentheses straight a close parentheses end cell equals cell 6 plus fraction numerator 3 straight a plus 3 over denominator 2 end fraction end cell end table end style 

Diketahui undefined, maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight f open parentheses straight p close parentheses end cell equals cell negative 3 end cell row cell 6 plus fraction numerator 3 straight p plus 3 over denominator 2 end fraction end cell equals cell negative 3 end cell row cell fraction numerator 3 straight p plus 3 over denominator 2 end fraction end cell equals cell negative 3 minus 6 end cell row cell fraction numerator 3 straight p plus 3 over denominator 2 end fraction end cell equals cell negative 9 end cell row cell 3 straight p plus 3 end cell equals cell negative 18 end cell row cell 3 straight p end cell equals cell negative 18 minus 3 end cell row cell 3 straight p end cell equals cell negative 21 end cell row straight p equals cell negative 21 over 3 end cell row straight p equals cell negative 7 end cell end table end style

Jadi, jawabannya adalah D.

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