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Diketahui dan . Maka, nilai p yang memenuhi dari adalah ....

Pertanyaan

Diketahui begin mathsize 14px style straight g open parentheses straight x minus 2 close parentheses equals 3 minus 2 straight x end style dan begin mathsize 14px style open parentheses straight f ring operator straight g close parentheses open parentheses straight x close parentheses equals 6 minus 3 straight x end style. Maka, nilai begin mathsize 14px style straight p end style yang memenuhi dari begin mathsize 14px style straight f open parentheses straight p close parentheses equals negative 3 end style adalah ....

  1. begin mathsize 14px style 11 over 3 end style

  2. begin mathsize 14px style 3 end style

  3. begin mathsize 14px style negative 3 end style

  4. undefined

  5. begin mathsize 14px style negative 11 over 3 end style

A. Rizky

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Jawaban

jawabannya adalah D.

Pembahasan

Pertama, kita cari undefined.

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight g open parentheses straight x minus 2 close parentheses end cell equals cell 3 minus 2 straight x end cell row blank equals cell negative 1 minus 2 straight x plus 4 end cell row blank equals cell negative 1 minus 2 open parentheses straight x minus 2 close parentheses end cell row cell straight g open parentheses straight x close parentheses end cell equals cell negative 1 minus 2 straight x end cell end table end style 

Sehingga

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses straight f ring operator straight g close parentheses open parentheses straight x close parentheses end cell equals cell 6 minus 3 straight x end cell row cell straight f open parentheses straight g open parentheses straight x close parentheses close parentheses end cell equals cell 6 minus 3 straight x end cell row cell straight f open parentheses negative 1 minus 2 straight x close parentheses end cell equals cell 6 minus 3 straight x end cell end table end style 

Misalkan begin mathsize 14px style negative 1 minus 2 straight x equals straight a rightwards arrow straight x equals fraction numerator straight a plus 1 over denominator negative 2 end fraction end style, maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight f open parentheses negative 1 minus 2 straight x close parentheses end cell equals cell 6 minus 3 straight x end cell row cell straight f open parentheses straight a close parentheses end cell equals cell 6 minus 3 open parentheses fraction numerator straight a plus 1 over denominator negative 2 end fraction close parentheses end cell row cell straight f open parentheses straight a close parentheses end cell equals cell 6 plus fraction numerator 3 straight a plus 3 over denominator 2 end fraction end cell end table end style 

Diketahui undefined, maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight f open parentheses straight p close parentheses end cell equals cell negative 3 end cell row cell 6 plus fraction numerator 3 straight p plus 3 over denominator 2 end fraction end cell equals cell negative 3 end cell row cell fraction numerator 3 straight p plus 3 over denominator 2 end fraction end cell equals cell negative 3 minus 6 end cell row cell fraction numerator 3 straight p plus 3 over denominator 2 end fraction end cell equals cell negative 9 end cell row cell 3 straight p plus 3 end cell equals cell negative 18 end cell row cell 3 straight p end cell equals cell negative 18 minus 3 end cell row cell 3 straight p end cell equals cell negative 21 end cell row straight p equals cell negative 21 over 3 end cell row straight p equals cell negative 7 end cell end table end style

Jadi, jawabannya adalah D.

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