Pertanyaan

Diketahui x  = 0 dan y  = 0 , bentuk sederhana ( 3 5 x − 7 y − 5 27 x − 5 y − 3 ) − 1 adalah....

Diketahui $x \neq = 0$ dan $y \neq = 0$ , bentuk sederhana $(\frac{27 x ^{- 5} y ^{- 3}}{3 ^{5} x ^{- 7} y ^{- 5}})^{- 1}$ adalah....

$fraction numerator 3 over denominator left parenthesis x y right parenthesis squared end fraction$
$fraction numerator 9 over denominator left parenthesis x y right parenthesis squared end fraction$

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Habis dalam

Klaim

N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Jawaban

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$open parentheses fraction numerator begin display style 27 x to the power of negative 5 end exponent y to the power of negative 3 end exponent end style over denominator begin display style 3 to the power of 5 x to the power of negative 7 end exponent y to the power of negative 5 end exponent end style end fraction close parentheses to the power of negative 1 end exponent$ $equals fraction numerator 9 over denominator left parenthesis x y right parenthesis squared end fraction$ .

Pembahasan

Dengan menggunakan sifat-sifat eksponen, maka: Jadi, .

Dengan menggunakan sifat-sifat eksponen, maka:

$equals open parentheses fraction numerator 3 to the power of 5 x to the power of negative 7 end exponent y to the power of negative 5 end exponent over denominator 3 cubed x to the power of negative 5 end exponent y to the power of negative 3 end exponent end fraction close parentheses equals 3 squared x to the power of negative 2 end exponent y to the power of negative 2 end exponent equals fraction numerator 9 over denominator x squared y squared end fraction equals fraction numerator 9 over denominator left parenthesis x y right parenthesis squared end fraction$

Jadi, $open parentheses fraction numerator begin display style 27 x to the power of negative 5 end exponent y to the power of negative 3 end exponent end style over denominator begin display style 3 to the power of 5 x to the power of negative 7 end exponent y to the power of negative 5 end exponent end style end fraction close parentheses to the power of negative 1 end exponent$ $equals fraction numerator 9 over denominator left parenthesis x y right parenthesis squared end fraction$ .