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Di dalam wadah 1 liter, dicampurkan 5 mol gas NO dan 0,7 mol gas CO 2 ​ sehingga terjadi reaksi kesetimbangan: NO ( g ) + CO 2 ​ ( g ) ⇌ NO 2 ​ ( g ) + CO ( g ) Bila pada saat kesetimbangan terdapat 0,5 mol gas . K c pada reaksi tersebut adalah. . . .

Di dalam wadah 1 liter, dicampurkan 5 mol gas NO dan 0,7 mol gas sehingga terjadi reaksi kesetimbangan:

Bila pada saat kesetimbangan terdapat 0,5 mol gas C O subscript 2. Kc pada reaksi tersebut adalah. . . .

  1. A. 0,016

  2. B. 0,025

  3. C. 0,040

  4. D. 0,500

  5. E. 2,400

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I. Solichah

Master Teacher

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Persamaan space reaksi colon space space N O space open parentheses g close parentheses space space space space plus space space space space C O subscript 2 space space space space space space space space space space rightwards arrow space space space N O subscript 2 space open parentheses g close parentheses space space space space space space plus space space space space space space space C O space open parentheses g close parentheses space  Mula space – space mula space space space space space space space space space space space space space 5 space mol space space space space space space space space space space 0 comma 7 space mol space space space space space space space space space space space space space space space space minus sign space space space space space space space space space space space space space space space space space space space space space space space minus sign space space  Reaksi space space space space space space space space space space space space space space space space space space space space space space 0 comma 2 space mol space space space space space space space space space space 0 comma 2 space mol space space space space space space space space space space space space space 0 comma 2 space mol space space space space space space space space space space space space space 0 comma 2 space mol space  top enclose Setimbang space space space space space space space space space space space space space space space space space 4 comma 8 space mol space space space space space space space space 0 comma 5 space mol space space space space space space space space space space space space 0 comma 2 space mol space space space space space space space space space space space space space space space 0 comma 2 space mol end enclose

K italic c equals fraction numerator open square brackets N O subscript 2 close square brackets open square brackets C O close square brackets over denominator open square brackets N O close square brackets open square brackets C O subscript 2 close square brackets end fraction equals fraction numerator left parenthesis 0 comma 2 right parenthesis left parenthesis 0 comma 2 right parenthesis over denominator left parenthesis 4 comma 8 right parenthesis left parenthesis 0 comma 5 right parenthesis end fraction equals 0 comma 016

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Dalam reaksi kesetimbangan 2 NO ( g ) ⇌ N 2 ​ ( g ) + O 2 ​ ( g ) , 1 mol gas NO terurai dalam wadah 1 L dan ternyata pada keadaan setimbang terdapat 40% volume gas O 2 ​ , nilai konstantan kesetimban...

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