Pertanyaan

Dari reaksi BrO 3 − ( aq ) + 5 Br − ( aq ) + 6 H + ( aq ) → 3 Br 2 ( l ) + 3 H 2 O ( l ) , laju awal ditentukan pada suhu 25 ∘ C dengan penambahan konsentrasi pereaksi yang berbeda sesuai dengan tabel: Laju awal pada percobaan kelima adalah .... (SIMAK UI 2017)

Dari reaksi

$BrO_{3}^{-} (aq) + 5 Br^{-} (aq) + 6 H^{+} (aq) \to 3 Br_{2} (l) + 3 H_{2} O (l)$ ,

laju awal ditentukan pada suhu $25^{\circ} C$ dengan penambahan konsentrasi pereaksi yang berbeda sesuai dengan tabel:

Laju awal pada percobaan kelima adalah ....

(SIMAK UI 2017)

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Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.

Pembahasan

Menghitung orde Pilih data dan yang sama, yaitu pada1 dan 2. Menghitung orde Pilih data dan yang sama, yaitu pada 1 dan 3. Menghitung orde Pilih data dan yang sama, yaitu pada 2 dan 4. Menghitung laju awal pada percobaan ke-5 Pilih data 5 dan 4 sebagai pembanding Jadi, jawaban yang benar adalah B.

Menghitung orde

Pilih data dan yang sama, yaitu pada 1 dan 2.

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight v subscript 1 over straight v subscript 2 end cell equals cell fraction numerator straight k open square brackets BrO subscript 3 superscript minus close square brackets subscript 1 to the power of straight x over denominator straight k open square brackets BrO subscript 3 superscript minus close square brackets subscript 2 to the power of straight x end fraction open square brackets Br to the power of minus close square brackets subscript 1 to the power of straight y over open square brackets Br to the power of minus close square brackets subscript 2 to the power of straight y open square brackets straight H to the power of plus close square brackets subscript 1 to the power of straight z over open square brackets straight H to the power of plus close square brackets subscript 2 to the power of straight z end cell row cell fraction numerator 7 comma 2 cross times 10 to the power of negative 4 end exponent over denominator 2 comma 4 cross times 10 to the power of negative 4 end exponent end fraction end cell equals cell fraction numerator straight k open square brackets 0 comma 15 close square brackets to the power of straight x over denominator straight k open square brackets 0 comma 05 close square brackets to the power of straight x end fraction open square brackets 0 comma 1 close square brackets to the power of straight y over open square brackets 0 comma 1 close square brackets to the power of straight y open square brackets 0 comma 1 close square brackets to the power of straight z over open square brackets 0 comma 1 close square brackets to the power of straight z end cell row cell fraction numerator 7 comma 2 cross times horizontal strike 10 to the power of negative 4 end exponent end strike over denominator 2 comma 4 cross times horizontal strike 10 to the power of negative 4 end exponent end strike end fraction end cell equals cell fraction numerator straight k open square brackets 0 comma 15 close square brackets to the power of straight x over denominator straight k open square brackets 0 comma 05 close square brackets to the power of straight x end fraction fraction numerator horizontal strike open square brackets 0 comma 1 close square brackets to the power of straight y end strike over denominator horizontal strike open square brackets 0 comma 1 close square brackets to the power of straight y end strike end fraction fraction numerator horizontal strike open square brackets 0 comma 1 close square brackets to the power of straight z end strike over denominator horizontal strike open square brackets 0 comma 1 close square brackets to the power of straight z end strike end fraction end cell row cell fraction numerator 7 comma 2 over denominator 2 comma 4 end fraction end cell equals cell fraction numerator 0 comma 15 to the power of straight x over denominator 0 comma 05 to the power of straight x end fraction end cell row cell 3 over 1 end cell equals cell 3 to the power of straight x over 1 to the power of straight x end cell row bold x bold equals bold 1 end table end style$

Menghitung orde

Pilih data dan yang sama, yaitu pada 1 dan 3.

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 1 over v subscript 3 end cell equals cell fraction numerator k open square brackets Br O subscript 3 to the power of minus sign close square brackets subscript 1 to the power of x over denominator k open square brackets Br O subscript 3 to the power of minus sign close square brackets subscript 3 to the power of x end fraction open square brackets Br to the power of minus sign close square brackets subscript 1 to the power of y over open square brackets Br to the power of minus sign close square brackets subscript 3 to the power of y open square brackets H to the power of plus sign close square brackets subscript 1 to the power of z over open square brackets H to the power of plus sign close square brackets subscript 3 to the power of z end cell row cell fraction numerator 7 comma 2 cross times 10 to the power of negative sign 4 end exponent over denominator 5 comma 76 cross times 10 to the power of negative sign 3 end exponent end fraction end cell equals cell fraction numerator k left square bracket 0 comma 15 right square bracket to the power of x over denominator k left square bracket 0 comma 15 right square bracket to the power of x end fraction space left square bracket 0 comma 1 right square bracket to the power of y over left square bracket 0 comma 2 right square bracket to the power of y left square bracket 0 comma 1 right square bracket to the power of z over left square bracket 0 comma 1 right square bracket to the power of z end cell row cell fraction numerator 7 comma 2 cross times 10 to the power of negative sign 4 end exponent over denominator 5 comma 76 cross times 10 to the power of negative sign 3 end exponent end fraction end cell equals cell fraction numerator horizontal strike k left square bracket 0 comma 15 right square bracket to the power of x end strike over denominator horizontal strike k left square bracket 0 comma 15 right square bracket to the power of x end strike end fraction left square bracket 0 comma 1 right square bracket to the power of y over left square bracket 0 comma 2 right square bracket to the power of y fraction numerator horizontal strike left square bracket 0 comma 1 right square bracket to the power of z end strike over denominator horizontal strike left square bracket 0 comma 1 right square bracket to the power of z end strike end fraction end cell row cell fraction numerator 0 comma 72 over denominator 5 comma 76 end fraction end cell equals cell fraction numerator 0 comma 1 to the power of y over denominator 0 comma 2 to the power of y end fraction end cell row cell 1 over 8 end cell equals cell 1 to the power of y over 2 to the power of y end cell row italic y bold equals bold 3 end table end style$

Menghitung orde

Pilih data dan yang sama, yaitu pada 2 dan 4.

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 2 over v subscript 4 end cell equals cell fraction numerator k open square brackets Br O subscript 3 to the power of minus sign close square brackets subscript 2 to the power of x over denominator k open square brackets Br O subscript 3 to the power of minus sign close square brackets subscript 4 to the power of x end fraction open square brackets Br to the power of minus sign close square brackets subscript 2 to the power of y over open square brackets Br to the power of minus sign close square brackets subscript 2 to the power of y open square brackets H to the power of plus sign close square brackets subscript 2 to the power of z over open square brackets H to the power of plus sign close square brackets subscript 2 to the power of z end cell row cell fraction numerator 2 comma 4 cross times 10 to the power of negative sign 4 end exponent over denominator 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end fraction end cell equals cell fraction numerator k left square bracket 0 comma 05 right square bracket to the power of x over denominator k left square bracket 0 comma 05 right square bracket to the power of x end fraction left square bracket 0 comma 1 right square bracket to the power of y over left square bracket 0 comma 1 right square bracket to the power of y left square bracket 0 comma 1 right square bracket to the power of z over left square bracket 0 comma 2 right square bracket to the power of z end cell row cell fraction numerator horizontal strike 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end strike over denominator horizontal strike 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end strike end fraction end cell equals cell fraction numerator horizontal strike k left square bracket 0 comma 05 right square bracket to the power of x end strike over denominator horizontal strike k left square bracket 0 comma 05 right square bracket to the power of x end strike end fraction fraction numerator horizontal strike left square bracket 0 comma 1 right square bracket to the power of y end strike over denominator horizontal strike left square bracket 0 comma 1 right square bracket to the power of y end strike end fraction left square bracket 0 comma 1 right square bracket to the power of z over left square bracket 0 comma 2 right square bracket to the power of z end cell row cell 1 over 1 end cell equals cell fraction numerator 0 comma 1 to the power of z over denominator 0 comma 2 to the power of z end fraction end cell row italic z bold equals bold 0 end table end style$

Menghitung laju awal pada percobaan ke-5

Pilih data 5 dan 4 sebagai pembanding

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 5 over v subscript 4 end cell equals cell fraction numerator k open square brackets Br O subscript 3 to the power of minus sign close square brackets subscript 5 to the power of x over denominator k open square brackets Br O subscript 3 to the power of minus sign close square brackets subscript 4 to the power of x end fraction open square brackets Br to the power of minus sign close square brackets subscript 5 to the power of y over open square brackets Br to the power of minus sign close square brackets subscript 2 to the power of y open square brackets H to the power of plus sign close square brackets subscript 5 to the power of z over open square brackets H to the power of plus sign close square brackets subscript 2 to the power of z end cell row cell fraction numerator v subscript 5 over denominator 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end fraction end cell equals cell fraction numerator k left square bracket 0 comma 2 right square bracket to the power of x over denominator k left square bracket 0 comma 05 right square bracket to the power of x end fraction left square bracket 0 comma 2 right square bracket to the power of y over left square bracket 0 comma 1 right square bracket to the power of y left square bracket 0 comma 2 right square bracket to the power of z over left square bracket 0 comma 2 right square bracket to the power of z end cell row cell fraction numerator v subscript 5 over denominator 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end fraction end cell equals cell fraction numerator k left square bracket 0 comma 2 right square bracket to the power of 1 over denominator k left square bracket 0 comma 05 right square bracket to the power of 1 end fraction fraction numerator left square bracket 0 comma 2 right square bracket cubed over denominator left square bracket 0 comma 1 right square bracket 3 end fraction left square bracket 0 comma 2 right square bracket to the power of 0 over left square bracket 0 comma 2 right square bracket to the power of 0 end cell row cell fraction numerator v subscript 5 over denominator 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end fraction end cell equals cell fraction numerator horizontal strike k left square bracket 0 comma 2 right square bracket to the power of 1 over denominator horizontal strike k left square bracket 0 comma 05 right square bracket to the power of 1 end fraction fraction numerator left square bracket 0 comma 2 right square bracket cubed over denominator left square bracket 0 comma 1 right square bracket 3 end fraction fraction numerator horizontal strike left square bracket 0 comma 2 right square bracket to the power of 0 end strike over denominator horizontal strike left square bracket 0 comma 2 right square bracket to the power of 0 end strike end fraction end cell row cell fraction numerator v subscript 5 over denominator 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end fraction end cell equals cell fraction numerator 0 comma 2 over denominator 0 comma 05 end fraction cross times fraction numerator 8 cross times 10 to the power of negative sign 3 end exponent over denominator 1 cross times 10 to the power of negative sign 3 end exponent end fraction end cell row cell italic v subscript bold 5 end cell bold equals cell bold 7 bold comma bold 68 bold cross times bold 10 to the power of bold minus sign bold 3 end exponent bold space italic M bold forward slash s end cell end table end style$

Jadi, jawaban yang benar adalah B.

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