Pertanyaan

Dari reaksi BrO 3 − ( aq ) + 5 Br − ( aq ) + 6 H + ( aq ) → 3 Br 2 ( l ) + 3 H 2 O ( l ) , laju awal ditentukan pada suhu 25 ∘ C dengan penambahan konsentrasi pereaksi yang berbeda sesuai dengan tabel: Laju awal pada percobaan kelima adalah .... (SIMAK UI 2017)

Dari reaksi

$BrO_{3}^{-} (aq) + 5 Br^{-} (aq) + 6 H^{+} (aq) \to 3 Br_{2} (l) + 3 H_{2} O (l)$ ,

laju awal ditentukan pada suhu $25^{\circ} C$ dengan penambahan konsentrasi pereaksi yang berbeda sesuai dengan tabel:

Laju awal pada percobaan kelima adalah ....

(SIMAK UI 2017)

F. Tri

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.

Pembahasan

Menghitung orde Pilih data dan yang sama, yaitu pada1 dan 2. Menghitung orde Pilih data dan yang sama, yaitu pada 1 dan 3. Menghitung orde Pilih data dan yang sama, yaitu pada 2 dan 4. Menghitung laju awal pada percobaan ke-5 Pilih data 5 dan 4 sebagai pembanding Jadi, jawaban yang benar adalah B.

Menghitung orde

Pilih data dan yang sama, yaitu pada 1 dan 2.

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell straight v subscript 1 over straight v subscript 2 end cell equals cell fraction numerator straight k open square brackets BrO subscript 3 superscript minus close square brackets subscript 1 to the power of straight x over denominator straight k open square brackets BrO subscript 3 superscript minus close square brackets subscript 2 to the power of straight x end fraction open square brackets Br to the power of minus close square brackets subscript 1 to the power of straight y over open square brackets Br to the power of minus close square brackets subscript 2 to the power of straight y open square brackets straight H to the power of plus close square brackets subscript 1 to the power of straight z over open square brackets straight H to the power of plus close square brackets subscript 2 to the power of straight z end cell row cell fraction numerator 7 comma 2 cross times 10 to the power of negative 4 end exponent over denominator 2 comma 4 cross times 10 to the power of negative 4 end exponent end fraction end cell equals cell fraction numerator straight k open square brackets 0 comma 15 close square brackets to the power of straight x over denominator straight k open square brackets 0 comma 05 close square brackets to the power of straight x end fraction open square brackets 0 comma 1 close square brackets to the power of straight y over open square brackets 0 comma 1 close square brackets to the power of straight y open square brackets 0 comma 1 close square brackets to the power of straight z over open square brackets 0 comma 1 close square brackets to the power of straight z end cell row cell fraction numerator 7 comma 2 cross times horizontal strike 10 to the power of negative 4 end exponent end strike over denominator 2 comma 4 cross times horizontal strike 10 to the power of negative 4 end exponent end strike end fraction end cell equals cell fraction numerator straight k open square brackets 0 comma 15 close square brackets to the power of straight x over denominator straight k open square brackets 0 comma 05 close square brackets to the power of straight x end fraction fraction numerator horizontal strike open square brackets 0 comma 1 close square brackets to the power of straight y end strike over denominator horizontal strike open square brackets 0 comma 1 close square brackets to the power of straight y end strike end fraction fraction numerator horizontal strike open square brackets 0 comma 1 close square brackets to the power of straight z end strike over denominator horizontal strike open square brackets 0 comma 1 close square brackets to the power of straight z end strike end fraction end cell row cell fraction numerator 7 comma 2 over denominator 2 comma 4 end fraction end cell equals cell fraction numerator 0 comma 15 to the power of straight x over denominator 0 comma 05 to the power of straight x end fraction end cell row cell 3 over 1 end cell equals cell 3 to the power of straight x over 1 to the power of straight x end cell row bold x bold equals bold 1 end table end style$

Menghitung orde

Pilih data dan yang sama, yaitu pada 1 dan 3.

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 1 over v subscript 3 end cell equals cell fraction numerator k open square brackets Br O subscript 3 to the power of minus sign close square brackets subscript 1 to the power of x over denominator k open square brackets Br O subscript 3 to the power of minus sign close square brackets subscript 3 to the power of x end fraction open square brackets Br to the power of minus sign close square brackets subscript 1 to the power of y over open square brackets Br to the power of minus sign close square brackets subscript 3 to the power of y open square brackets H to the power of plus sign close square brackets subscript 1 to the power of z over open square brackets H to the power of plus sign close square brackets subscript 3 to the power of z end cell row cell fraction numerator 7 comma 2 cross times 10 to the power of negative sign 4 end exponent over denominator 5 comma 76 cross times 10 to the power of negative sign 3 end exponent end fraction end cell equals cell fraction numerator k left square bracket 0 comma 15 right square bracket to the power of x over denominator k left square bracket 0 comma 15 right square bracket to the power of x end fraction space left square bracket 0 comma 1 right square bracket to the power of y over left square bracket 0 comma 2 right square bracket to the power of y left square bracket 0 comma 1 right square bracket to the power of z over left square bracket 0 comma 1 right square bracket to the power of z end cell row cell fraction numerator 7 comma 2 cross times 10 to the power of negative sign 4 end exponent over denominator 5 comma 76 cross times 10 to the power of negative sign 3 end exponent end fraction end cell equals cell fraction numerator horizontal strike k left square bracket 0 comma 15 right square bracket to the power of x end strike over denominator horizontal strike k left square bracket 0 comma 15 right square bracket to the power of x end strike end fraction left square bracket 0 comma 1 right square bracket to the power of y over left square bracket 0 comma 2 right square bracket to the power of y fraction numerator horizontal strike left square bracket 0 comma 1 right square bracket to the power of z end strike over denominator horizontal strike left square bracket 0 comma 1 right square bracket to the power of z end strike end fraction end cell row cell fraction numerator 0 comma 72 over denominator 5 comma 76 end fraction end cell equals cell fraction numerator 0 comma 1 to the power of y over denominator 0 comma 2 to the power of y end fraction end cell row cell 1 over 8 end cell equals cell 1 to the power of y over 2 to the power of y end cell row italic y bold equals bold 3 end table end style$

Menghitung orde

Pilih data dan yang sama, yaitu pada 2 dan 4.

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 2 over v subscript 4 end cell equals cell fraction numerator k open square brackets Br O subscript 3 to the power of minus sign close square brackets subscript 2 to the power of x over denominator k open square brackets Br O subscript 3 to the power of minus sign close square brackets subscript 4 to the power of x end fraction open square brackets Br to the power of minus sign close square brackets subscript 2 to the power of y over open square brackets Br to the power of minus sign close square brackets subscript 2 to the power of y open square brackets H to the power of plus sign close square brackets subscript 2 to the power of z over open square brackets H to the power of plus sign close square brackets subscript 2 to the power of z end cell row cell fraction numerator 2 comma 4 cross times 10 to the power of negative sign 4 end exponent over denominator 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end fraction end cell equals cell fraction numerator k left square bracket 0 comma 05 right square bracket to the power of x over denominator k left square bracket 0 comma 05 right square bracket to the power of x end fraction left square bracket 0 comma 1 right square bracket to the power of y over left square bracket 0 comma 1 right square bracket to the power of y left square bracket 0 comma 1 right square bracket to the power of z over left square bracket 0 comma 2 right square bracket to the power of z end cell row cell fraction numerator horizontal strike 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end strike over denominator horizontal strike 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end strike end fraction end cell equals cell fraction numerator horizontal strike k left square bracket 0 comma 05 right square bracket to the power of x end strike over denominator horizontal strike k left square bracket 0 comma 05 right square bracket to the power of x end strike end fraction fraction numerator horizontal strike left square bracket 0 comma 1 right square bracket to the power of y end strike over denominator horizontal strike left square bracket 0 comma 1 right square bracket to the power of y end strike end fraction left square bracket 0 comma 1 right square bracket to the power of z over left square bracket 0 comma 2 right square bracket to the power of z end cell row cell 1 over 1 end cell equals cell fraction numerator 0 comma 1 to the power of z over denominator 0 comma 2 to the power of z end fraction end cell row italic z bold equals bold 0 end table end style$

Menghitung laju awal pada percobaan ke-5

Pilih data 5 dan 4 sebagai pembanding

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 5 over v subscript 4 end cell equals cell fraction numerator k open square brackets Br O subscript 3 to the power of minus sign close square brackets subscript 5 to the power of x over denominator k open square brackets Br O subscript 3 to the power of minus sign close square brackets subscript 4 to the power of x end fraction open square brackets Br to the power of minus sign close square brackets subscript 5 to the power of y over open square brackets Br to the power of minus sign close square brackets subscript 2 to the power of y open square brackets H to the power of plus sign close square brackets subscript 5 to the power of z over open square brackets H to the power of plus sign close square brackets subscript 2 to the power of z end cell row cell fraction numerator v subscript 5 over denominator 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end fraction end cell equals cell fraction numerator k left square bracket 0 comma 2 right square bracket to the power of x over denominator k left square bracket 0 comma 05 right square bracket to the power of x end fraction left square bracket 0 comma 2 right square bracket to the power of y over left square bracket 0 comma 1 right square bracket to the power of y left square bracket 0 comma 2 right square bracket to the power of z over left square bracket 0 comma 2 right square bracket to the power of z end cell row cell fraction numerator v subscript 5 over denominator 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end fraction end cell equals cell fraction numerator k left square bracket 0 comma 2 right square bracket to the power of 1 over denominator k left square bracket 0 comma 05 right square bracket to the power of 1 end fraction fraction numerator left square bracket 0 comma 2 right square bracket cubed over denominator left square bracket 0 comma 1 right square bracket 3 end fraction left square bracket 0 comma 2 right square bracket to the power of 0 over left square bracket 0 comma 2 right square bracket to the power of 0 end cell row cell fraction numerator v subscript 5 over denominator 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end fraction end cell equals cell fraction numerator horizontal strike k left square bracket 0 comma 2 right square bracket to the power of 1 over denominator horizontal strike k left square bracket 0 comma 05 right square bracket to the power of 1 end fraction fraction numerator left square bracket 0 comma 2 right square bracket cubed over denominator left square bracket 0 comma 1 right square bracket 3 end fraction fraction numerator horizontal strike left square bracket 0 comma 2 right square bracket to the power of 0 end strike over denominator horizontal strike left square bracket 0 comma 2 right square bracket to the power of 0 end strike end fraction end cell row cell fraction numerator v subscript 5 over denominator 2 comma 4 cross times 10 to the power of negative sign 4 end exponent end fraction end cell equals cell fraction numerator 0 comma 2 over denominator 0 comma 05 end fraction cross times fraction numerator 8 cross times 10 to the power of negative sign 3 end exponent over denominator 1 cross times 10 to the power of negative sign 3 end exponent end fraction end cell row cell italic v subscript bold 5 end cell bold equals cell bold 7 bold comma bold 68 bold cross times bold 10 to the power of bold minus sign bold 3 end exponent bold space italic M bold forward slash s end cell end table end style$

Jadi, jawaban yang benar adalah B.

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