Pertanyaan

Dari percobaan pengukuran laju reaksi diperoleh data sebagai berikut. Dari data tersebut, dapat disimpulkan bahwa orde reaksi totalnya adalah . . .

Dari percobaan pengukuran laju reaksi diperoleh data sebagai berikut.

Dari data tersebut, dapat disimpulkan bahwa orde reaksi totalnya adalah . . .

Y. Rochmawatie

Master Teacher

Jawaban terverifikasi

Pembahasan

Rumus laju reaksi: Menghitung orde reaksi terhadap A Menghitung orde reaksi terhadap B Orde reaksi total Berdasarkan perhitungan di atas, pilihan jawaban yang paling tepat adalah C.

Rumus laju reaksi:

Menghitung orde reaksi terhadap A

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 2 over v subscript 3 end cell equals cell fraction numerator k open square brackets A close square brackets subscript 2 superscript m open square brackets B close square brackets subscript 2 superscript n over denominator k open square brackets A close square brackets subscript 3 superscript m open square brackets B close square brackets subscript 3 superscript n end fraction end cell row cell fraction numerator begin display style bevelled 1 over t subscript 2 end style over denominator begin display style bevelled 1 over t subscript 3 end style end fraction end cell equals cell fraction numerator k open square brackets A close square brackets subscript 2 superscript m open square brackets B close square brackets subscript 2 superscript n over denominator k open square brackets A close square brackets subscript 3 superscript m open square brackets B close square brackets subscript 3 superscript n end fraction end cell row cell fraction numerator begin display style bevelled 1 fourth end style over denominator begin display style bevelled 1 fourth end style end fraction end cell equals cell fraction numerator k open square brackets 0 comma 1 close square brackets to the power of m open square brackets 0 comma 3 close square brackets to the power of n over denominator k open square brackets 0 comma 2 close square brackets to the power of m open square brackets 0 comma 3 close square brackets to the power of n end fraction end cell row 1 equals cell open square brackets 1 half close square brackets to the power of m end cell row 1 equals cell open square brackets 1 half close square brackets to the power of 0 end cell row italic m bold equals bold 0 end table end style$

Menghitung orde reaksi terhadap B

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 1 over v subscript 2 end cell equals cell fraction numerator k open square brackets A close square brackets subscript 1 superscript m open square brackets B close square brackets subscript 1 superscript n over denominator k open square brackets A close square brackets subscript 2 superscript m open square brackets B close square brackets subscript 2 superscript n end fraction end cell row cell fraction numerator begin display style bevelled 1 over t subscript 1 end style over denominator begin display style bevelled 1 over t subscript 2 end style end fraction end cell equals cell fraction numerator k open square brackets A close square brackets subscript 1 superscript m open square brackets B close square brackets subscript 1 superscript n over denominator k open square brackets A close square brackets subscript 2 superscript m open square brackets B close square brackets subscript 2 superscript n end fraction end cell row cell fraction numerator begin display style bevelled 1 over 36 end style over denominator begin display style bevelled 1 fourth end style end fraction end cell equals cell fraction numerator k open square brackets 0 comma 1 close square brackets to the power of m open square brackets 0 comma 1 close square brackets to the power of n over denominator k open square brackets 0 comma 1 close square brackets to the power of m open square brackets 0 comma 3 close square brackets to the power of n end fraction end cell row cell 4 over 36 end cell equals cell open square brackets 1 third close square brackets to the power of n end cell row cell 1 over 9 end cell equals cell open square brackets 1 third close square brackets to the power of n end cell row cell open square brackets 1 third close square brackets squared end cell equals cell open square brackets 1 third close square brackets to the power of n end cell row italic n bold equals bold 2 row blank blank blank row blank blank blank row blank blank blank row blank blank blank end table end style$

Orde reaksi total

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell Orde space reaksi space total space end cell equals cell m and n end cell row cell Orde space reaksi space total end cell equals cell 0 plus 2 end cell row cell bold Orde bold space bold reaksi bold space bold total end cell bold equals bold 2 end table end style

Berdasarkan perhitungan di atas, pilihan jawaban yang paling tepat adalah C.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

5.0 (6 rating)

Pertanyaan serupa

Untuk reaksi A + B + C → D + E diperoleh data: Orde reaksi adalah ....

5.0

Jawaban terverifikasi

Pada reaksi P + Q → R diperoleh data: Orde reaksinya adalah...

4.3

Jawaban terverifikasi

Disajikan data yang hasil percobaan reaksi: A + B → C sebagai berikut. Jika [A] dinaikkan 4 kali, [B] tetap, laju reaksi tetap. Jika [A] dan [B] masing-masing dinaikkan 2 kali, laju reaksi me...

3.6

Jawaban terverifikasi

Data hasil percobaan reaksi: pada suhu tertentu sebagai berikut. Orde reaksi terhadap CO dan O 2 berturut-turut adalah ...

5.0

Jawaban terverifikasi

Pada percobaan reaksi P + 2 Q → PQ 2 diperoleh data-data percobaan sebagai berikut. Tentukan: b. orde reaksi terhadap Q

5.0

Jawaban terverifikasi