Pertanyaan

p = 14 − 13 1 dan q = 14 + 13 1 maka nilai p 2 + pq + q 2 =...

$p = \frac{1}{14 - 13}$ dan $q = \frac{1}{14 + 13}$ maka nilai $p^{2} + pq + q^{2}$ =...

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Habis dalam

Klaim

N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

jadi,

$tilde space straight p plus straight q equals fraction numerator 1 over denominator square root of 14 space minus space square root of 13 end fraction plus space fraction numerator 1 over denominator square root of 14 space plus space square root of 13 end fraction equals fraction numerator open parentheses square root of 14 space plus space square root of 13 close parentheses space plus space open parentheses square root of 14 space minus space square root of 13 close parentheses over denominator open parentheses square root of 14 close parentheses squared space minus open parentheses square root of 13 close parentheses squared space space end fraction equals fraction numerator 2 square root of 14 over denominator 14 minus 13 end fraction equals 2 square root of 14 tilde space pq equals fraction numerator 1 over denominator square root of 14 space minus space square root of 13 end fraction. space fraction numerator 1 over denominator square root of 14 space plus space square root of 13 end fraction equals fraction numerator 1 over denominator open parentheses square root of 14 close parentheses squared space minus open parentheses square root of 13 close parentheses squared space end fraction equals fraction numerator 1 over denominator 14 minus 13 end fraction equals 1$

jadi,

equals open parentheses p squared plus q squared close parentheses plus p q equals open parentheses p plus q close parentheses squared minus 2 p q plus p q equals open parentheses p plus q close parentheses squared minus p q equals open parentheses 2 square root of 14 close parentheses squared minus 1 equals 56 minus 1 equals 55