Pertanyaan

Dalam volume 2 liter dipanaskan 1 mol gas SO 3 sehingga terjadi kesetimbangan: 2 SO 3 (g) ⇄ 2SO 2 (g) + O 2 (g) Keadaan Zat Mol SO 3 Mol SO 2 Mol O 2 Mula-mula 1 - - Reaksi 0,50 0,50 0,25 Setimbang 0,50 0,50 0,25 Harga Kc pada kesetimbangan tersebut adalah ...

Dalam volume 2 liter dipanaskan 1 mol gas SO₃sehingga terjadi kesetimbangan:

2 SO₃ (g) $⇄$ 2SO₂(g) + O₂(g)

Keadaan Zat	Mol SO₃	Mol SO₂	Mol O₂
Mula-mula	1	-	-
Reaksi	0,50	0,50	0,25
Setimbang	0,50	0,50	0,25

Harga Kc pada kesetimbangan tersebut adalah ...

$text Kc= end text fraction numerator open square brackets 0 comma 5 divided by 2 close square brackets over denominator open square brackets 0 comma 5 divided by 2 close square brackets open square brackets 0 comma 25 divided by 2 close square brackets end fraction$
$text Kc= end text fraction numerator open square brackets 0 comma 5 divided by 2 close square brackets open square brackets 0 comma 5 divided by 2 close square brackets over denominator open square brackets 0 comma 25 divided by 2 close square brackets end fraction$
$text Kc= end text fraction numerator open square brackets 0 comma 5 close square brackets squared open square brackets 0 comma 25 close square brackets over denominator open square brackets 0 comma 5 close square brackets squared end fraction$
$text Kc= end text fraction numerator open square brackets 0 comma 5 close square brackets over denominator open square brackets 0 comma 5 close square brackets end fraction$
$text Kc= end text fraction numerator open square brackets 0 comma 5 divided by 2 close square brackets squared open square brackets 0 comma 25 divided by 2 close square brackets over denominator open square brackets 0 comma 5 divided by 2 close square brackets squared end fraction$

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Pembahasan

Harga tetapan kesetimbangan (Kc), dihitung saat keadaan setimbang. Sehingga :

$text Kc end text equals fraction numerator left square bracket S O subscript 2 right square bracket squared right parenthesis left square bracket O subscript 2 right square bracket over denominator left square bracket S O subscript 3 right square bracket squared end fraction equals fraction numerator left square bracket 0 comma 50 divided by 2 right square bracket squared open square brackets 0 comma 25 divided by 2 close square brackets over denominator left square bracket 0 comma 50 divided by 2 right square bracket squared end fraction$

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