Dalam volume 2 liter dipanaskan 1 mol gas SO3​ sehingga terjadi kesetimbangan: 2 SO3​(g) ⇆ 2 SO2​(g) + O2​(g) Data yang diperoleh sebagai berikut: Harga Kc pada kesetimbangan tersebut adalah ...

Pertanyaan

Dalam volume 2 liter dipanaskan 1 mol gas SO subscript 3 sehingga terjadi kesetimbangan:

2 space SO subscript 3 left parenthesis straight g right parenthesis space leftwards arrow over rightwards arrow space 2 space SO subscript 2 left parenthesis straight g right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis

Data yang diperoleh sebagai berikut:

Harga Kc pada kesetimbangan tersebut adalah ...

  1. Kc equals fraction numerator left square bracket 0 comma 5 divided by 2 right square bracket over denominator left square bracket 0 comma 5 divided by 2 right square bracket left square bracket 0 comma 25 divided by 2 right square bracket end fraction

  2. Kc equals fraction numerator left square bracket 0 comma 5 divided by 2 right square bracket left square bracket 0 comma 5 divided by 2 right square bracket over denominator left square bracket 0 comma 25 divided by 2 right square bracket end fraction

  3. Kc equals fraction numerator left square bracket 0 comma 5 right square bracket squared left square bracket 0 comma 25 right square bracket over denominator left square bracket 0 comma 5 right square bracket squared end fraction

  4. Kc equals fraction numerator left square bracket 0 comma 5 right square bracket over denominator left square bracket 0 comma 5 right square bracket end fraction

  5. Kc equals fraction numerator left square bracket 0 comma 5 divided by 2 right square bracket squared left square bracket 0 comma 25 divided by 2 right square bracket over denominator left square bracket 0 comma 5 divided by 2 right square bracket squared end fraction

D. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

2 space SO subscript 3 left parenthesis straight g right parenthesis space leftwards arrow over rightwards arrow space 2 space SO subscript 2 left parenthesis straight g right parenthesis space plus space straight O subscript 2 left parenthesis straight g right parenthesis

S=0,50 mol      0,50 mol          0,25 mol

Dalam volume 2 Liter

Kc equals fraction numerator left square bracket produk right square bracket to the power of koefisien over denominator left square bracket reaktan right square bracket to the power of koefisien end fraction equals fraction numerator left square bracket SO subscript 2 right square bracket squared cross times left square bracket straight O subscript 2 right square bracket to the power of 1 over denominator left square bracket SO subscript 3 right square bracket squared end fraction equals fraction numerator left square bracket begin display style fraction numerator 0 comma 5 over denominator 2 end fraction end style right square bracket squared cross times left square bracket begin display style fraction numerator 0 comma 25 over denominator 2 end fraction end style right square bracket to the power of 1 over denominator left square bracket begin display style fraction numerator 0 comma 50 over denominator 2 end fraction end style right square bracket squared end fraction

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