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Bila K subscript sp space Ca F subscript 2 equals 4 cross times 10 to the power of negative sign 11 end exponent, maka kelarutan Ca F subscript 2 dalam 0 comma 1 space M space Ca Cl subscript 2 adalah ....

  1. 2 comma 3 cross times 10 to the power of negative sign 5 end exponent 

  2. 3 comma 2 cross times 10 to the power of negative sign 5 end exponent 

  3. 1 comma 28 cross times 10 to the power of negative sign 4 end exponent 

  4. space 3 comma 4 cross times 10 to the power of negative sign 4 end exponent 

  5. 4 comma 3 cross times 10 to the power of negative sign 4 end exponent 

M. Juliana

Master Teacher

Mahasiswa/Alumni Universitas Negeri Medan

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.

Pembahasan

Penambahan ion senama akan memperkecil kelarutan.

Konsentrasi Ca to the power of 2 plus sign dapat ditentukan dari reaksi ionisasi senyawa Ca Cl subscript 2 berikut:


 Ca Cl subscript 2 equilibrium Ca to the power of 2 plus sign and 2 Cl to the power of minus sign 0 comma 01 space space space space space space bold 0 bold comma bold 01 bold space bold space bold space 0 comma 02  


Berdasarkan reaksi di atas, konsentrasi Ca to the power of 2 plus sign adalah 0,01 M.

Reaksi untuk kelarutan Ca F subscript 2 adalah:


Ca F subscript 2 equilibrium Ca to the power of 2 plus sign and 2 F to the power of minus sign


maka, rumus hasil kali kelarutannya adalah


table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp end cell equals cell open square brackets Ca to the power of 2 plus sign close square brackets open square brackets F to the power of minus sign close square brackets squared end cell row cell K subscript sp end cell equals cell open square brackets Ca to the power of 2 plus sign close square brackets open square brackets 2 s close square brackets squared end cell row cell 4 cross times 10 to the power of negative sign 11 end exponent end cell equals cell open square brackets 0 comma 01 space M close square brackets open square brackets 4 s squared close square brackets end cell row cell 4 s squared end cell equals cell fraction numerator 4 cross times 10 to the power of negative sign 11 end exponent over denominator 0 comma 01 space M end fraction end cell row blank equals cell 4 cross times 10 to the power of negative sign 9 end exponent end cell row cell s squared end cell equals cell fraction numerator 4 cross times 10 to the power of negative sign 9 end exponent over denominator 4 end fraction end cell row cell s squared end cell equals cell 10 cross times 10 to the power of negative sign 10 end exponent end cell row s equals cell square root of 10 cross times 10 to the power of negative sign 10 end exponent end root end cell row blank equals cell 3 comma 2 cross times 10 to the power of negative sign 5 end exponent end cell end table 


Dengan demikian, kelarutannya adalah 3 comma 2 cross times 10 to the power of negative sign 5 end exponent.

Jadi, jawaban yang benar adalah B.

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