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besar perbandingan gelombang foton yang dipancarkan bila elektron pada atom H dieksitasi mengikuti deret Balmer ke dua dengan deret Pfund pertama adalah sekitar

Pertanyaan

besar perbandingan gelombang foton yang dipancarkan bila elektron pada atom H dieksitasi mengikuti deret Balmer ke dua dengan deret Pfund pertama adalah sekitar begin mathsize 14px style straight h equals 6 comma 6 cross times 10 to the power of negative 34 space space end exponent Js comma space straight c equals 3 cross times 10 to the power of 8 space straight m divided by straight s space dan space straight R equals 1 comma 1 cross times 10 to the power of 7 divided by straight m end style 

  1. 10undefined 

  2. 15undefined 

  3. 20undefined 

  4. 25undefined 

  5. 3undefined 

Pembahasan Soal:

untuk deret Balmer

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell nilai space fB end cell row cell 1 over straight lambda end cell equals cell straight R space left parenthesis 1 over 2 squared minus 1 over 4 squared right parenthesis end cell row cell 1 over straight lambda end cell equals cell straight R space left parenthesis 1 fourth minus 1 over 16 right parenthesis end cell row cell 1 over straight lambda end cell equals cell straight R space left parenthesis 3 over 16 right parenthesis end cell row straight lambda equals cell 16 over 3 straight R end cell row straight f equals cell straight c over straight lambda end cell row straight f equals cell fraction numerator straight c over denominator 16 over 3 straight R end fraction end cell row straight f equals cell fraction numerator 3 space cR over denominator 16 end fraction end cell row blank blank cell nilai space fP end cell row cell 1 over straight lambda end cell equals cell straight R space left parenthesis 1 over 5 squared minus 1 over 6 squared right parenthesis end cell row cell 1 over straight lambda end cell equals cell straight R space left parenthesis 1 over 25 minus 1 over 36 right parenthesis end cell row cell 1 over straight lambda end cell equals cell straight R space left parenthesis 11 over 900 right parenthesis end cell row straight lambda equals cell 900 over 11 straight R end cell row straight f equals cell straight c over straight lambda end cell row straight f equals cell fraction numerator straight c over denominator 900 over 11 straight R end fraction end cell row straight f equals cell fraction numerator 11 space cR over denominator 900 end fraction end cell row blank blank blank row cell fB over fP end cell equals cell fraction numerator fraction numerator 11 space cR over denominator 900 end fraction over denominator fraction numerator 3 space cR over denominator 16 end fraction end fraction end cell row cell fB over fP end cell equals cell 15 comma 34 end cell row blank blank blank end table end style 

Jadi jawaban yang benar adalah B.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 14 Maret 2021

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