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Besar intensitas gelombang cahaya pada suatu titik P bila amplitudo medan listrik di titik tersebut sebesar adalah....

Pertanyaan

Besar intensitas gelombang cahaya pada suatu titik P bila amplitudo medan listrik di titik tersebut sebesar4 comma 0 cross times 10 to the power of negative 2 end exponent space straight N divided by straight C adalah....

  1. fraction numerator 1 over denominator 3 straight pi end fraction cross times 10 to the power of negative 5 end exponent space watt divided by straight m squared

  2. fraction numerator 2 over denominator 3 straight pi end fraction cross times 10 to the power of negative 5 end exponent space watt divided by straight m squared

  3. fraction numerator 4 over denominator 3 straight pi end fraction cross times 10 to the power of negative 5 end exponent space watt divided by straight m squared

  4. fraction numerator 5 over denominator 3 straight pi end fraction cross times 10 to the power of negative 5 end exponent space watt divided by straight m squared

  5. fraction numerator 7 over denominator 3 straight pi end fraction cross times 10 to the power of negative 5 end exponent space watt divided by straight m squared

Pembahasan Soal:

Berdasarkan persamaan yang berlaku pada energi gelombang elektromagnetik, intensitas gelombang dapat ditentukan dengan persamaan:

S equals fraction numerator E subscript m. B subscript m over denominator 2 mu subscript 0 end fraction

Pada soal telah diketahui nilai E subscript m equals 4 cross times 10 to the power of negative 2 end exponent space bevelled straight N over straight C, untuk dapat menghitung intensitas gelombang cahaya terlebih dahulu harus menghitung nilai kuat medan magnetnya (B subscript m).

B subscript m equals E subscript m over c equals fraction numerator 4 cross times 10 to the power of negative 2 end exponent over denominator 3 cross times 10 to the power of 8 end fraction equals 4 over 3 cross times 10 to the power of negative 10 end exponent space straight J divided by Cs

Maka nilai intensitas cahaya adalah

S equals fraction numerator E subscript m. B subscript m over denominator 2 mu subscript 0 end fraction equals fraction numerator 4 cross times 10 to the power of negative 2 end exponent. space begin display style 4 over 3 end style cross times 10 to the power of negative 10 end exponent over denominator 2. space 4 straight pi cross times 10 to the power of negative 7 end exponent end fraction equals fraction numerator 2 over denominator 3 straight pi end fraction cross times 10 to the power of negative 5 end exponent space watt divided by straight m squared

Oleh karena itu, jawabannya adalah B

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 Mei 2021

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