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Berapa mol dan berapa atom masing-masing unsur yang terdapat dalam zat-zat berikut?  6,84 g C12​H22​O11​ 62 g Ca3​(PO4​)2​ 12,3 g MgSO4​.7H2​O

Pertanyaan

Berapa mol dan berapa atom masing-masing unsur yang terdapat dalam zat-zat berikut?space 

  1. 6,84 g begin mathsize 14px style C subscript 12 H subscript 22 O subscript 11 end style
  2. 62 g begin mathsize 14px style Ca subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end style
  3. 12,3 g begin mathsize 14px style Mg S O subscript 4 point 7 H subscript 2 O end style 

Pembahasan Soal:

Mol merupakan jumlah tertentu untuk menentukan banyaknya suatu zat yang mikroskopis. Jumlah mol dapat dicari dengan membagi massa zat dibagi dengan massa molekul relatif zat tersebut.


n equals massa over Mr 


Hubungan mol dengan jumlah pertikel adalah


table attributes columnalign right center left columnspacing 0px end attributes row N equals cell mol cross times L end cell row blank equals cell mol cross times 6 comma 02 cross times 10 to the power of 23 space partikel end cell end table 


dimana L adalah Bilangan Avogadro dan N adalah jumlah partikel

1. C subscript 12 H subscript 22 O subscript 11

 Menentukan mol C subscript 12 H subscript 22 O subscript 11 

table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript r end cell equals cell left parenthesis 12 cross times A subscript r space C right parenthesis plus left parenthesis 22 cross times A subscript r space H right parenthesis plus left parenthesis 11 cross times A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 12 cross times 12 right parenthesis plus left parenthesis 22 cross times 1 right parenthesis plus left parenthesis 11 cross times 16 right parenthesis end cell row blank equals cell 144 plus 22 plus 176 end cell row blank equals 342 end table 
table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript C subscript 12 H subscript 22 O subscript 11 end subscript end cell equals cell fraction numerator 6 comma 84 over denominator 342 end fraction end cell row blank equals cell 0 comma 02 space mol end cell end table  

Menghitung mol masing-masing unsur

table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Unsur end cell equals cell Jumlah space atom space unsur cross times Mol subscript C subscript 12 H subscript 22 O subscript 11 end subscript end cell row cell n subscript C end cell equals cell 12 cross times left parenthesis 0 comma 02 right parenthesis end cell row blank equals cell 0 comma 24 space mol end cell row blank blank blank row cell n subscript H end cell equals cell 22 cross times left parenthesis 0 comma 02 right parenthesis end cell row blank equals cell 0 comma 44 space mol end cell row blank blank blank row cell n subscript O end cell equals cell 11 cross times left parenthesis 0 comma 02 right parenthesis end cell row blank equals cell 0 comma 22 space mol end cell end table     

Menghitung jumlah partikel atom tiap unsur

table attributes columnalign right center left columnspacing 0px end attributes row cell N subscript Unsur end cell equals cell mol space unsur cross times left parenthesis 6 comma 02 cross times 10 to the power of 23 right parenthesis end cell row cell N subscript C end cell equals cell 0 comma 24 cross times left parenthesis 6 comma 02 cross times 10 to the power of 23 right parenthesis end cell row blank equals cell 1 comma 4448 cross times 10 to the power of 23 space atom end cell row blank blank blank row cell N subscript H end cell equals cell 0 comma 44 cross times left parenthesis 6 comma 02 cross times 10 to the power of 23 right parenthesis end cell row blank equals cell 2 comma 6488 cross times 10 to the power of 23 space atom end cell row blank blank blank row cell N subscript O end cell equals cell 0 comma 22 cross times left parenthesis 6 comma 02 cross times 10 to the power of 23 right parenthesis end cell row blank equals cell 1 comma 3244 cross times 10 to the power of 23 space atom end cell end table  


2. Ca subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 

Menentukan mol Ca subscript 3 open parentheses P O subscript 4 close parentheses subscript 2

table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript r end cell equals cell left parenthesis 3 cross times A subscript r space Ca right parenthesis plus left parenthesis 2 cross times A subscript r space P right parenthesis plus left parenthesis 8 cross times A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 3 cross times 40 right parenthesis plus left parenthesis 2 cross times 31 right parenthesis plus left parenthesis 8 cross times 16 right parenthesis end cell row blank equals cell 120 plus 62 plus 128 end cell row blank equals 310 end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Ca subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end subscript end cell equals cell 62 over 310 end cell row blank equals cell 0 comma 2 space mol end cell end table

Menghitung mol masing-masing unsur 

table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Unsur end cell equals cell Banyak space atom space unsur cross times Mol subscript Ca subscript 3 open parentheses P O subscript 4 close parentheses subscript 2 end subscript end cell row cell n subscript Ca end cell equals cell 3 cross times left parenthesis 0 comma 2 right parenthesis end cell row blank equals cell 0 comma 6 space mol end cell row blank blank blank row cell n subscript P end cell equals cell 2 cross times left parenthesis 0 comma 2 right parenthesis end cell row blank equals cell 0 comma 4 space mol end cell row blank blank blank row cell n subscript O end cell equals cell 8 cross times left parenthesis 0 comma 2 right parenthesis end cell row blank equals cell 1 comma 6 space mol end cell end table   

Menghitung jumlah partikel atom tiap unsur

table attributes columnalign right center left columnspacing 0px end attributes row cell N subscript Unsur end cell equals cell mol space unsur cross times left parenthesis 6 comma 02 cross times 10 to the power of 23 right parenthesis end cell row cell N subscript Ca end cell equals cell 0 comma 6 cross times left parenthesis 6 comma 02 cross times 10 to the power of 23 right parenthesis end cell row blank equals cell 3 comma 612 cross times 10 to the power of 23 space atom end cell row blank blank blank row cell N subscript P end cell equals cell 0 comma 4 cross times left parenthesis 6 comma 02 cross times 10 to the power of 23 right parenthesis end cell row blank equals cell 2 comma 408 cross times 10 to the power of 23 space atom end cell row blank blank blank row cell N subscript O end cell equals cell 1 comma 6 cross times left parenthesis 6 comma 02 cross times 10 to the power of 23 right parenthesis end cell row blank equals cell 9 comma 632 cross times 10 to the power of 23 space atom end cell end table   


3. Mg S O subscript 4 

 Menentukan mol Mg S O subscript 4  

table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript r end cell equals cell left parenthesis A subscript r space Mg right parenthesis plus left parenthesis A subscript r space S right parenthesis plus left parenthesis 4 cross times A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 24 right parenthesis plus left parenthesis 32 right parenthesis plus left parenthesis 4 cross times 16 right parenthesis end cell row blank equals cell 24 plus 32 plus 64 end cell row blank equals 120 end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Mg S O subscript 4 end subscript end cell equals cell fraction numerator 12 comma 3 over denominator 120 end fraction end cell row blank equals cell 0 comma 1025 space mol end cell end table   

Menghitung mol masing-masing unsur

table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Unsur end cell equals cell Jumlah space atom space unsur cross times Mol subscript Mg S O subscript 4 end subscript end cell row cell n subscript Mg end cell equals cell 1 cross times left parenthesis 0 comma 1025 right parenthesis end cell row blank equals cell 0 comma 1025 space mol end cell row blank blank blank row cell n subscript S end cell equals cell 1 cross times left parenthesis 0 comma 1025 right parenthesis end cell row blank equals cell space 0 comma 1025 space mol end cell row blank blank blank row cell n subscript O end cell equals cell 4 cross times left parenthesis 0 comma 1025 right parenthesis end cell row blank equals cell space 0 comma 41 space mol end cell end table  

Menghitung jumlah partikel atom tiap unsur 

table attributes columnalign right center left columnspacing 0px end attributes row cell N subscript Unsur end cell equals cell mol space unsur cross times left parenthesis 6 comma 02 cross times 10 to the power of 23 right parenthesis end cell row cell N subscript Mg end cell equals cell 0 comma 1025 cross times left parenthesis 6 comma 02 cross times 10 to the power of 23 right parenthesis end cell row blank equals cell 6 comma 17 cross times 10 to the power of 22 space atom end cell row blank blank blank row Ns equals cell 0 comma 1025 cross times left parenthesis 6 comma 02 cross times 10 to the power of 23 right parenthesis end cell row blank equals cell 6 comma 17 cross times 10 to the power of 22 space atom end cell row blank blank blank row cell N subscript O end cell equals cell 0 comma 41 cross times left parenthesis 6 comma 02 cross times 10 to the power of 23 right parenthesis end cell row blank equals cell 2 comma 47 cross times 10 to the power of 23 space atom end cell end table  

Dengan demikian, maka jawaban yang tepat adalah sesuai penjelasan di atas.

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

I. Solichah

Terakhir diupdate 07 Oktober 2021

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