Pertanyaan

Bentuk sederhana dari adalah....

Bentuk sederhana dari $begin mathsize 14px style fraction numerator cos left parenthesis A plus B right parenthesis plus cos left parenthesis A minus B right parenthesis over denominator sin open parentheses A plus B close parentheses plus sin left parenthesis A minus B right parenthesis end fraction end style$ adalah....

sin A
cos A
tan A
cot A
sin B

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H. Eka

Master Teacher

Mahasiswa/Alumni Universitas Pendidikan Indonesia

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Pembahasan

$begin mathsize 12px style fraction numerator cos left parenthesis A plus B right parenthesis plus cos left parenthesis A minus B right parenthesis over denominator sin open parentheses A plus B close parentheses plus sin left parenthesis A minus B right parenthesis end fraction equals fraction numerator 2 cos open parentheses 1 half open parentheses open parentheses A plus B close parentheses plus open parentheses A minus B close parentheses close parentheses close parentheses space cos open parentheses 1 half open parentheses open parentheses A plus B close parentheses minus open parentheses A minus B close parentheses close parentheses close parentheses over denominator 2 sin open parentheses 1 half open parentheses open parentheses A plus B close parentheses plus open parentheses A minus B close parentheses close parentheses close parentheses space cos open parentheses 1 half open parentheses open parentheses A plus B close parentheses minus open parentheses A minus B close parentheses close parentheses close parentheses end fraction equals fraction numerator 2 cos open parentheses 1 half open parentheses 2 A close parentheses close parentheses space cos open parentheses 1 half open parentheses 2 B close parentheses close parentheses over denominator 2 sin open parentheses 1 half open parentheses 2 A close parentheses close parentheses space cos open parentheses 1 half open parentheses 2 B close parentheses close parentheses end fraction equals fraction numerator 2 cos space A space cos space B over denominator 2 sin space A space cos space B end fraction equals fraction numerator up diagonal strike 2 cos space A space up diagonal strike cos space B end strike over denominator up diagonal strike 2 sin space A space up diagonal strike cos space B end strike end fraction equals fraction numerator cos space A over denominator sin space A end fraction equals cot space A end style$