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Pertanyaan

Bentuk sederhana dari begin mathsize 14px style left parenthesis a to the power of negative 3 end exponent b to the power of 5 c to the power of negative 8 end exponent right parenthesis cubed over left parenthesis a to the power of 4 b to the power of negative 3 end exponent c to the power of 10 right parenthesis to the power of negative 2 end exponent end style adalah ... 

  1. begin mathsize 14px style fraction numerator a over denominator b to the power of 9 c cubed end fraction end style 

  2. begin mathsize 14px style fraction numerator a over denominator b to the power of 8 c cubed end fraction end style 

  3. begin mathsize 14px style fraction numerator b to the power of 9 over denominator a c to the power of 4 end fraction end style 

  4. begin mathsize 14px style fraction numerator b to the power of 9 over denominator a c cubed end fraction end style 

  5. begin mathsize 14px style fraction numerator b to the power of 8 over denominator a squared c to the power of 4 end fraction end style 

N. Puspita

Master Teacher

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah C.

Pembahasan

Dengan menggunakan sifat-sifat dari bilangan berpangkat (eksponen), didapat:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses a to the power of negative 3 end exponent b to the power of 5 c to the power of negative 8 end exponent close parentheses cubed over open parentheses a to the power of 4 b to the power of negative 3 end exponent c to the power of 10 close parentheses to the power of negative 2 end exponent end cell equals cell fraction numerator open parentheses a to the power of negative 9 end exponent b to the power of 15 c to the power of negative 24 end exponent close parentheses over denominator open parentheses a to the power of negative 8 end exponent b to the power of 6 c to the power of negative 20 end exponent close parentheses end fraction end cell row blank equals cell a to the power of negative 9 minus left parenthesis negative 8 right parenthesis end exponent b to the power of 15 minus 6 end exponent c to the power of negative 24 minus left parenthesis negative 20 right parenthesis end exponent end cell row blank equals cell a to the power of negative 1 end exponent b to the power of 9 c to the power of negative 4 end exponent end cell row blank equals cell fraction numerator b to the power of 9 over denominator a c to the power of 4 end fraction end cell end table end style 

Jadi, bentuk sederhananya adalah begin mathsize 14px style fraction numerator b to the power of 9 over denominator a c to the power of 4 end fraction end style.

Dengan demikian, jawaban yang tepat adalah C.

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