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Bentuk sederhana dari 24 12 3 27 x − 72 y 24 ​ ​ ​ adalah ....

Bentuk sederhana dari  adalah ....

  1. begin mathsize 14px style 24 x to the power of 12 y to the power of 4 end style 

  2. begin mathsize 14px style 12 x to the power of 6 y squared end style 

  3. begin mathsize 14px style fraction numerator 24 y cubed over denominator x to the power of 6 end fraction end style 

  4. begin mathsize 14px style fraction numerator 12 y squared over denominator x to the power of 6 end fraction end style 

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A. Khairunisa

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah D.

jawaban yang tepat adalah D.

Pembahasan

Perhatikan bahwa Jadi, hasil dari adalah . Dengan demikian, jawaban yang tepat adalah D.

Perhatikan bahwa

begin mathsize 11px style table attributes columnalign right center left columnspacing 0px end attributes row cell square root of 24 square root of 12 cube root of 27 x to the power of negative 72 end exponent y to the power of 24 end root end root end root end cell equals cell square root of 24 square root of 12 open parentheses 3 cubed x to the power of negative 72 end exponent y to the power of 24 close parentheses to the power of 1 third end exponent end root end root blank end cell row blank equals cell square root of 24 square root of 12 open parentheses 3 to the power of 3 cross times 1 third end exponent x to the power of negative 72 cross times 1 third end exponent y to the power of 24 cross times 1 third end exponent close parentheses end root end root end cell row blank equals cell square root of 24 square root of 12 open parentheses 3 x to the power of negative 24 end exponent y to the power of 8 close parentheses end root end root end cell row blank equals cell square root of 24 square root of 36 x to the power of negative 24 end exponent y to the power of 8 end root end root end cell row blank equals cell square root of 24 square root of 6 squared x to the power of negative 24 end exponent y to the power of 8 end root end root end cell row blank equals cell square root of 24 open parentheses 6 squared x to the power of negative 24 end exponent y to the power of 8 close parentheses to the power of 1 half end exponent end root end cell row blank equals cell square root of 24 open parentheses 6 to the power of 2 cross times 1 half end exponent x to the power of negative 24 cross times 1 half end exponent y to the power of 8 cross times 1 half end exponent close parentheses end root end cell row blank equals cell square root of 24 open parentheses 6 x to the power of negative 12 end exponent y to the power of 4 close parentheses end root end cell row blank equals cell square root of 144 times x to the power of negative 12 end exponent times y to the power of 4 end root end cell row blank equals cell square root of 12 squared times x to the power of negative 12 end exponent times y to the power of 4 end root end cell row blank equals cell open parentheses 12 squared times x to the power of negative 12 end exponent times y to the power of 4 close parentheses to the power of 1 half end exponent end cell row blank equals cell 12 to the power of 2 cross times 1 half end exponent times x to the power of negative 12 cross times 1 half end exponent times y to the power of 4 cross times 1 half end exponent end cell row blank equals cell 12 times x to the power of negative 6 end exponent times y squared end cell row blank equals cell fraction numerator 12 y squared over denominator x to the power of 6 end fraction end cell end table end style   

Jadi, hasil dari undefined adalah undefined.

Dengan demikian, jawaban yang tepat adalah D.

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