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Bentuk sederhana dari  adalah ...

Pertanyaan

Bentuk sederhana dari open parentheses fraction numerator x cubed y to the power of negative 1 end exponent z over denominator x squared y to the power of negative 2 end exponent z squared end fraction close parentheses cubed adalah ...

  1. x to the power of negative 3 end exponent y to the power of negative 3 end exponent z to the power of negative 4 end exponent 

  2. x to the power of negative 3 end exponent y to the power of negative 3 end exponent z to the power of 4 

  3. x y to the power of negative 3 end exponent z to the power of negative 4 end exponent 

  4. x y to the power of negative 3 end exponent z squared 

  5. x cubed y cubed z to the power of negative 3 end exponent 

Pembahasan Soal:

Perlu diingat sifat bentuk bilangan berpangkat atau eksponen yaitu:

a to the power of m space colon space a to the power of n equals a to the power of m minus n end exponent open parentheses a to the power of m close parentheses to the power of n equals a to the power of m cross times n end exponent open parentheses a cross times b close parentheses to the power of m equals a to the power of m cross times b to the power of m

Dengan menggunakan sifat bentuk bilangan berpangkat di atas, kita dapat menentukan bentuk sederhana dari open parentheses fraction numerator x cubed y to the power of negative 1 end exponent z over denominator x squared y to the power of negative 2 end exponent z squared end fraction close parentheses cubed seperti berikut:

open parentheses fraction numerator x cubed y to the power of negative 1 end exponent z over denominator x squared y to the power of negative 2 end exponent z squared end fraction close parentheses cubed equals open parentheses x to the power of 3 minus 2 end exponent y to the power of negative 1 plus 2 end exponent z to the power of 1 minus 2 end exponent close parentheses cubed space space space space space space space space space space space space space space space space space space space equals open parentheses x y z to the power of negative 1 end exponent close parentheses cubed space space space space space space space space space space space space space space space space space space space equals x cubed y cubed z to the power of negative 3 end exponent

Sehingga, bentuk sederhana dari open parentheses fraction numerator x cubed y to the power of negative 1 end exponent z over denominator x squared y to the power of negative 2 end exponent z squared end fraction close parentheses cubed adalah x cubed y cubed z to the power of negative 3 end exponent.

Jadi, jawaban yang tepat adalah E.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 27 Juli 2021

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