Pertanyaan

Bentuk sederhana dari ...

Bentuk sederhana dari $open parentheses fraction numerator 2 a to the power of 5 b to the power of negative 5 end exponent over denominator 32 a to the power of 9 b to the power of negative 1 end exponent end fraction close parentheses to the power of negative 1 end exponent equals$ ...

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

Klaim

A. Acfreelance

Master Teacher

Jawaban terverifikasi

Pembahasan

$open parentheses fraction numerator 2 a to the power of 5 b to the power of negative 5 end exponent over denominator 32 a to the power of 9 b to the power of negative 1 end exponent end fraction close parentheses to the power of negative 1 end exponent equals fraction numerator 2 to the power of negative 1 end exponent a to the power of negative 5 end exponent b to the power of 5 over denominator open parentheses 2 to the power of 5 close parentheses to the power of negative 1 end exponent a to the power of negative 9 end exponent b to the power of 1 end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 2 to the power of negative 1 minus open parentheses negative 5 close parentheses end exponent a to the power of negative 5 minus open parentheses negative 9 close parentheses end exponent b to the power of 5 minus 1 end exponent space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 2 to the power of 4 a to the power of 4 b to the power of 4 space space space space space space space space space space space space space space space space space space space space space space space space space space space equals left parenthesis 2 a b right parenthesis to the power of 4$

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

4.9 (10 rating)

Ervia Rahmadanti

Makasih ❤️

Najwa Azkiya

Bantu banget Pembahasan lengkap banget Ini yang aku cari! Mudah dimengerti

Nana

Ini yang aku cari! Mudah dimengerti Pembahasan lengkap banget

Intan Nuraini

Ini yang aku cari!

Pertanyaan serupa

Jika diketahui bahwa a = 4 , b = 2 , dan c = 2 1 , maka nilai dari ( a − 1 ) 2 × c − 3 b 4 = …

4.8

Jawaban terverifikasi

$open parentheses fraction numerator 8 a to the power of negative 9 end exponent b to the power of negative 2 end exponent over denominator 64 a to the power of negative 6 end exponent b end fraction close parentheses to the power of negative 1 end exponent equals horizontal ellipsis$

0.0

Jawaban terverifikasi

Bentuk pangkat positif dari

5.0

Jawaban terverifikasi

Jika diketahui x = 1 3 x = 3 1 , y = 5 1 , z = 2 , Maka nilai dari x - 4 y z - 2 x - 3 y 2 z - 4 =… x − 3 y 2 z − 4 x − 4 y z − 2 = …

4.8

Jawaban terverifikasi

$open parentheses fraction numerator a to the power of negative 4 end exponent b squared c over denominator a b to the power of negative 6 end exponent c cubed end fraction close parentheses to the power of 4 equals horizontal ellipsis$

4.5

Jawaban terverifikasi