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Anilin ( C 6 ​ H 5 ​ NH 2 ​ ) sebagai basa lemah memiliki pH larutan sebesar 9. Konsentrasi larutan anilin sebesar (diketahui ) ….

 

Anilin (  ) sebagai basa lemah memiliki pH larutan sebesar 9. Konsentrasi larutan anilin sebesar (diketahui Error converting from MathML to accessible text.  ) ….

  1.  begin mathsize 12px style 7 , 4 cross times 10 to the power of negative 2 end exponent straight straight M end style 

  2. begin mathsize 12px style 1 , 35 cross times 10 to the power of negative 5 end exponent straight straight M end style 

  3. begin mathsize 12px style 7 , 4 cross times 10 to the power of negative 4 end exponent straight straight M end style 

  4. 0,0135 M

  5. 0,135 M

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Pembahasan

Selanjutnya, dalam menentukan konsentrasi perhitungannya menjadi

begin mathsize 12px style pOH equals 14 minus pH space pOH equals 14 minus 9 equals 5 pOH equals negative log invisible function application open square brackets OH to the power of minus close square brackets open square brackets OH to the power of minus close square brackets equals 10 to the power of negative pOH end exponent equals 10 to the power of negative 5 end exponent end style 

Selanjutnya, dalam menentukan konsentrasi perhitungannya menjadi

begin mathsize 12px style open square brackets OH to the power of minus close square brackets equals square root of straight K subscript straight b cross times straight M end root open square brackets OH to the power of minus close square brackets squared equals straight K subscript straight b cross times straight M straight M equals open square brackets OH to the power of minus close square brackets squared over straight K subscript straight b equals fraction numerator open square brackets 10 to the power of negative 5 end exponent close square brackets squared over denominator 7 , 4 cross times 10 to the power of negative 10 end exponent end fraction straight M equals fraction numerator 10 to the power of negative 10 end exponent over denominator 7 , 4 cross times 10 to the power of negative 10 end exponent end fraction straight M equals fraction numerator 10 cross times 10 to the power of negative 11 end exponent over denominator 7 , 4 cross times 10 to the power of negative 10 end exponent end fraction straight M equals 0 , 135 end style 

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Suatu basa lemah memiliki Kb 1 ​ = 1 , 5 × 1 0 − 5 serta nilai Kb 2 ​ = 1 , 2 × 1 0 − 12 sehingga jika dianalisis konsentrasi [ OH − ] maka persamaan matematis yang digunakan yaitu ….

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