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∫ sin 4 x cos 4 x d x adalah...

 adalah...

  1. fraction numerator 3 x over denominator 128 end fraction minus 1 over 64 sin space 2 x plus 1 over 256 sin space 4 x plus C

  2. fraction numerator 3 x over denominator 128 end fraction plus 1 over 64 sin space 2 x plus 1 over 256 sin space 4 x plus C

  3. fraction numerator 3 x over denominator 64 end fraction minus 1 over 128 sin space 4 x plus 1 over 512 sin space 4 x plus C

  4. fraction numerator 3 x over denominator 128 end fraction minus 32 space sin space 4 x plus 124 space sin space 8 x plus C

  5. fraction numerator 3 x over denominator 128 end fraction minus 1 over 128 sin space 4 x plus 1 over 1024 space sin space 8 x plus C

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Jawaban terverifikasi

Jawaban

jawaban yang tepat adalah E.

jawaban yang tepat adalah E.

Pembahasan

Karena kedua pangkatnya bilangan genap, untuk menentukan penyelesaiannya gunakan: Kesamaan setengah sudut Sehingga Jadi, jawaban yang tepat adalah E.

Karena kedua pangkatnya bilangan genap, untuk menentukan penyelesaiannya gunakan:

Kesamaan setengah sudut sin squared x equals fraction numerator 1 minus cos space 2 x over denominator 2 end fraction space dan space cos squared straight x equals fraction numerator 1 plus cos 2 straight x over denominator 2 end fraction comma

Sehingga

integral sin to the power of 4 x space cos to the power of 4 x space d x equals integral left parenthesis sin squared x right parenthesis squared left parenthesis cos squared x right parenthesis squared d x equals integral open parentheses fraction numerator 1 minus cos 2 x over denominator 2 end fraction close parentheses squared open parentheses fraction numerator 1 plus cos 2 x over denominator 2 end fraction close parentheses d x equals 1 over 16 integral left parenthesis 1 minus 2 space cos 2 x plus cos squared 2 x right parenthesis left parenthesis 1 plus 2 space cos 2 x plus cos squared 2 x right parenthesis d x equals 1 over 16 integral open parentheses 1 minus 2 cos squared 2 x plus cos to the power of 4 2 x close parentheses d x equals 1 over 16 integral d x minus 1 over 8 integral cos squared 2 x space d x plus 1 over 16 integral cos to the power of 4 2 x space d x equals 1 over 16 integral d x minus 1 over 8 integral fraction numerator 1 plus cos 4 x over denominator 2 end fraction plus 1 over 16 integral open parentheses fraction numerator 1 plus cos 4 x over denominator 2 end fraction close parentheses squared d x equals 1 over 16 integral d x minus 1 over 8 integral fraction numerator 1 plus cos 4 x over denominator 2 end fraction plus 1 over 64 integral open parentheses 1 plus 2 space cos 4 x plus cos squared 4 x close parentheses squared d x equals 1 over 16 integral d x minus 1 over 8 integral fraction numerator 1 plus cos 4 x over denominator 2 end fraction plus 1 over 64 integral d x plus 1 over 32 integral cos 4 x d x plus 1 over 64 integral open parentheses fraction numerator 1 plus cos 8 x over denominator 2 end fraction close parentheses d x equals 1 over 16 integral d x minus 1 over 8 integral fraction numerator 1 plus cos 4 x over denominator 2 end fraction plus 1 over 64 integral d x plus 1 over 32 integral cos 4 x space d x plus 1 over 128 integral d x plus integral 1 over 128 cos 8 x space d x equals 1 over 16 integral d x minus 1 over 16 integral d x minus 1 over 16 integral c p s 4 x space d x plus 1 over 64 integral d x plus 1 over 32 integral cos 4 x space d x plus 1 over 128 integral d x plus integral 1 over 128 cos 8 x space d x equals 3 over 128 integral d x minus 1 over 32 integral cos 4 x space d x plus 1 over 128 integral cos 8 x space d x equals fraction numerator 3 x over denominator 128 end fraction minus 1 over 128 sin 4 x plus 1 over 1024 sin 8 x plus C

Jadi, jawaban yang tepat adalah E.

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