Pertanyaan

x → 0 lim x 2 + tan 2 x + sin x 5 x + 2 sin x + 8 x cos x = … + 3 m u .

$x \to 0 lim \frac{5 x + 2 sin x + 8 x cos x}{x ^{2} + tan 2 x + sin x} = \dots + 3 m u .$

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Habis dalam

Klaim

F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

Jawaban terverifikasi

Pembahasan

$limit as x rightwards arrow 0 of invisible function application fraction numerator 5 x plus 2 sin invisible function application x plus 8 x cos invisible function application x over denominator x squared plus tan invisible function application 2 x plus sin invisible function application x end fraction. fraction numerator 1 over x over denominator 1 over x end fraction limit as x rightwards arrow 0 of invisible function application fraction numerator fraction numerator 5 x over denominator x end fraction plus fraction numerator 2 sin invisible function application x over denominator x end fraction plus fraction numerator 8 x cos invisible function application x over denominator x end fraction over denominator x squared over x plus fraction numerator tan invisible function application 2 x over denominator x end fraction plus fraction numerator sin invisible function application x over denominator x end fraction end fraction limit as x rightwards arrow 0 of invisible function application fraction numerator 5 plus 2 plus 8 cos invisible function application x over denominator x plus 2 plus 1 end fraction fraction numerator 5 plus 2 plus 8 cos invisible function application 0 over denominator 0 plus 2 plus 1 end fraction fraction numerator 5 plus 2 plus 8 open parentheses 1 close parentheses over denominator 2 plus 1 end fraction equals 15 over 3 equals 5$