Pertanyaan

A ka r − aka r p ers amaan x 2 − 12 x + p = 0 a d a l ah x 1 d an x 2 . J ika x 1 − x 2 = 2 , maka ni l ai p = ....

$A ka r - aka r p ers amaan x^{2} - 12 x + p = 0 a d a l ah x_{1} d an x_{2} . J ika x_{1} - x_{2} = 2, maka ni l ai p = ....$

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

Klaim

N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

$A k a r minus a k a r space p e r s a m a a n space k u a d r a t space straight space stack 1 with underbrace below with a below a x squared stack stack negative 12 with underbrace below with b below x plus stack p with underbrace below with c below equals 0 space a d a l a h space x subscript 1 space d a n space x subscript 2. space space D i k e t a h u i space d a r i space s o a l space x subscript 1 minus x subscript 2 equals 2 S u d a h space d i k e t a h u i space b a h w a space x subscript 1 plus x subscript 2 equals negative fraction numerator negative 12 over denominator 1 end fraction equals 12 U n t u k space m e n g e t a h u i space n i l a i space p comma space a k a n space d i c a r i space t e r l e b i h space d a h u l u space n i l a i space d a r i space x subscript 1 space d a n space x subscript 2 table row cell x subscript 1 minus x subscript 2 equals 2 space space space space space space space space space space space end cell row cell bottom enclose stack x subscript 1 plus x subscript 2 equals 12 space space space space space plus with _ below end enclose end cell row cell space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space 2 x subscript 1 equals 14 space ⟺ space space x subscript 1 equals 14 over 2 equals 7 end cell end table S u b s t i t u s i k a n space n i l a i space x subscript 1 equals 7 space k e space s a l a h space s a t u space p e r s a m a a n comma space m i s a l k a n space d i p i l i h space p e r s a m a a n space x subscript 1 minus x subscript 2 equals 2. space A k i b a t n y a space 7 minus x subscript 2 equals 2 space ⟺ space x subscript 2 equals 5 S e h i n g g a comma space n i l a i space p space y a i t u space colon x subscript 1. x subscript 2 equals c over a ⟺ 7 space. space 5 equals p over 1 ⟺ 35 equals p J a d i comma space n i l a i space p space a d a l a h space 35$

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

0.0 (0 rating)

Pertanyaan serupa

Persamaan kuadrat 2 x 2 − p x + 1 = 0 dengan p > 0, mempunyai akar-akar α d an β . Jika x 2 − 5 x + q = 0 mempunyai akar-akar α 2 1 d an β 2 1 maka nilai dari q - p adalah....

0.0

Jawaban terverifikasi

[UN 2011] Akar-akar persamaan kuadrat 3 x 2 − x + 9 = 0 adalah x 1 dan x 2 . Nilai dari x 2 x 1 + x 1 x 2 adalah...

0.0

Jawaban terverifikasi

Persamaan x 2 − a x − ( a + 1 ) = 0 mempunyai akar-akar x 1 > 1 d an x 2 < 1 ketika a bernilai....

0.0

Jawaban terverifikasi

P ers amaan k u a d r a t 2 x 2 − 7 x + 6 = 0 m e m p u n y ai aka r − aka r α d an β . De n g an d e mikian ni l ai d a r i ( α + β ) 2 = ....

0.0

Jawaban terverifikasi

Jika jumlah kuadrat akar-akar real persamaan kuadrat x 2 − x − p = 0 sama dengan kuadrat jumlah kebalikan akar-akar persamaan x 2 − p x − 1 = 0 , maka nilai p adalah ...

0.0

Jawaban terverifikasi