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Pertanyaan

J ika r a t aan d a r i ( a − 2 ) , ( b + 3 ) , ( c + 5 ) a d a l ah 6 , maka r a t aan d a r i ( a + 4 ) , ( b + 6 ) , ( c − 1 ) a d a l ah

  1. 5

  2. 6

  3. 7

  4. 8

  5. 9

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N. Rahayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

6 equals fraction numerator a minus 2 plus b plus 3 plus c plus 5 over denominator 3 end fraction a plus b plus c plus 6 equals 18 a plus b plus c equals 12  B e r i k u t n y a space c a r i space r a t a space – space r a t a space d a r i space left parenthesis a plus 4 right parenthesis comma left parenthesis b plus 6 right parenthesis comma left parenthesis c minus 1 right parenthesis fraction numerator a plus 4 plus b plus 6 plus c minus 1 over denominator 3 end fraction equals fraction numerator a plus b plus c plus 9 over denominator 3 end fraction equals fraction numerator 12 plus 9 over denominator 3 end fraction equals 7

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J i k a space r a t a a n space d a r i space x subscript 1 comma x subscript 2 comma horizontal ellipsis comma x n space a d a l a h space a comma space m a k a space j u m l a h a n space d a r i space open parentheses 1 third x subscript 1 plus 3 close parentheses comma space open parentheses 1 third x subscript 2 plus 5 close parentheses space.... comma open parentheses 1 third x subscript n plus open parentheses 2 n minus 1 close parentheses close parentheses space a d a l a h space...

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