Pertanyaan

k = 4 ∑ 10 k + 3 k − 2 = ....

$k = 4 \sum 10 \frac{k - 2}{k + 3} = ....$

$sum from k equals 1 to 7 of fraction numerator k plus 1 over denominator k plus 6 end fraction$
$sum from k equals 1 to 8 of fraction numerator k plus 1 over denominator k plus 6 end fraction$
$sum from k equals 1 to 8 of fraction numerator k minus 1 over denominator k plus 6 end fraction$
$sum from k equals 1 to 7 of fraction numerator k plus 1 over denominator k plus 7 end fraction$
$sum from k equals 1 to 6 of fraction numerator k plus 1 over denominator k plus 7 end fraction$

F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

Jawaban terverifikasi

Jawaban

jawaban yang benar adalah A.

Pembahasan

Misal, . Substitusikan pada notasi sigma Jadi, Oleh karena itu, jawaban yang benar adalah A.

Misal, k equals x plus 3 . Substitusikan pada notasi sigma

$table attributes columnalign right center left columnspacing 0px end attributes row cell sum from k equals 4 to 10 of fraction numerator k minus 2 over denominator k plus 3 end fraction end cell equals cell sum from x plus 3 equals 4 to 10 of fraction numerator left parenthesis x plus 3 right parenthesis minus 2 over denominator left parenthesis x plus 3 right parenthesis plus 3 end fraction end cell row blank equals cell sum from x equals 4 minus 3 to 10 minus 3 of fraction numerator x plus 1 over denominator x plus 6 end fraction end cell row blank equals cell sum from x equals 1 to 7 of fraction numerator x plus 1 over denominator x plus 6 end fraction end cell end table$

Jadi, $sum from k equals 4 to 10 of fraction numerator k minus 2 over denominator k plus 3 end fraction equals sum from k equals 1 to 7 of fraction numerator k plus 1 over denominator k plus 6 end fraction$

Oleh karena itu, jawaban yang benar adalah A.