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B i l a f : R → R d i t e n t u kan o l e h f ( x ) = x 2 d an f − 1 in v ers f maka f − 1 ({ 4 , 25 }) ia l ah him p u nan ...

  1. left curly bracket x vertical line 2 less or equal than x less or equal than 5 right curly bracket

  2. left curly bracket x vertical line minus 5 less or equal than x less or equal than 2 right curly bracket

  3. left curly bracket x vertical line 2 less or equal than x less or equal than 5 space a t a u space minus 5 less or equal than x minus 2 right curly bracket

  4. left curly bracket x vertical line 2 less than x less or equal than 5 right curly bracket

  5. left curly bracket x vertical line 2 less than x less than 5 right curly bracket

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D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

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Pembahasan

f left parenthesis x right parenthesis equals x squared  r to the power of negative 1 end exponent left parenthesis x right parenthesis equals x squared  y equals x squared  x equals square root of y  f to the power of negative 1 end exponent left parenthesis x right parenthesis equals square root of x  f to the power of negative 1 end exponent left parenthesis 4 comma 25 right parenthesis colon  f to the power of negative 1 end exponent left parenthesis 4 right parenthesis equals square root of 4 equals 2  f to the power of negative 1 end exponent left parenthesis 25 right parenthesis equals square root of 25 equals 5  H P equals left curly bracket x vertical line 2 less or equal than x less or equal than 5 right curly bracket

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Diketahui f ( x ) = 5 x + 6 , g − 1 ( x ) = 5 x − 9 x − 5 ​ ; x  = 5 9 ​ dan ( h ∘ g ) − 1 ( x ) = 3 x − 11 . Tentukan: a. rumus fungsi g .

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