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Pertanyaan

Hasil ∫ 0 1 ​ ( x 3 + 2 x − 5 ) dx = ....

  1. negative 16 over 4

  2. negative 15 over 4

  3. 0

  4. 15 over 4

  5. 16 over 4

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F. Kurnia

Master Teacher

Mahasiswa/Alumni Universitas Jember

Jawaban terverifikasi

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Pembahasan

integral subscript 0 superscript 1 left parenthesis x cubed plus 2 x minus 5 right parenthesis d x equals open square brackets 1 fourth x to the power of 4 plus 2 over 2 x squared minus 5 x close square brackets subscript 0 superscript 1  equals open curly brackets 1 fourth left parenthesis 1 right parenthesis to the power of 4 plus 2 over 2 left parenthesis 1 right parenthesis squared minus 5 left parenthesis 1 right parenthesis close curly brackets minus open curly brackets 1 fourth left parenthesis 0 right parenthesis to the power of 4 plus 2 over 2 left parenthesis 0 right parenthesis squared minus 5 left parenthesis 0 right parenthesis close curly brackets  equals 1 fourth plus 2 over 2 minus 5 equals negative 15 over 4

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Pertanyaan serupa

∫ − 2 2 ​ ( 3 x 2 + 4 ) dx = ...

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5.0

Jawaban terverifikasi

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