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S e ban y ak 12 , 8 g r am s u l f u r d i o k s i d a d ibaka r d e n g an 3 , 2 g r am g a s o k s i g e n d a l am r u an g t er t u t u p m e n g ha s i l kan g a s s u l f u r t r i o k s i d a m e n u r u t re ak s i : 2 S O 2 ​ ( g ) + O 2 ​ ( g ) → 2 S O 3 ​ ( g ) G a s s u l f u r t r i o k s i d a y an g t er b e n t u k se ban y ak .... ( A r S = 32 ; 0 = 16 )

  1.  8 gram

  2. 9 gram

  3. 10 gram

  4. 11 gram

  5. 16 gram

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D. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

stack 2 S O subscript 2 with 12 comma 8 space g r a m below space plus space stack O subscript 2 space left parenthesis g right parenthesis with 3 comma 2 space g r a m below space rightwards arrow space 2 space S O subscript 3 space end subscript left parenthesis g right parenthesis left parenthesis d a l a m space r u a n g space t e r t u t u p right parenthesis space  space D i tan y a space colon space g a s space s u l f u r space t r i o k s i d a space y a n g space t e r b e n t u k space ? space  U n t u k space m e n g e t a h u i space g a s space s u l f u r space t r i o k s i d a space y a n g space t e r b e n t u k comma space p e r l u space d i k e t a h u i space b a h w a space k o n s e p space d a r i space s o a l space i n i space m e n g g u n a k a n space k o n s e p space H u k u m space L a v o i s i e r space left parenthesis H u k u m space y a n g space m e l i b a t k a n space p e r p i n d a h a n space m a t e r i space d a n space e n e r g i space p a d a space s i s t e m space t e r t u t u p comma space m a k a space s i s t e m space a k a n space t e t a p space k o n s tan right parenthesis comma space j a d i space m a s s a space a w a l space d a n space m a s s a space a k h i r space r e a k s i space a k a n space t e t a p space s a m a. space M a k a space d a r i space i t u comma space m a s s a space a k h i r space d a r i space p r o d u k n y a space a d a l a h space 12 comma 8 space g r a m space plus space 3 comma 2 space g r a m space equals space 16 space g r a m.

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Perhatikan persamaan reaksi: SrH 2 ​ ( s ) + 2 H 2 ​ O ( l ) → Sr ( OH ) 2 ​ ( s ) + 2 H 2 ​ ( g ) Tunjukkan bahwa hukum kekekalan massa berlaku untuk persamaan reaksi tersebut.

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