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∫ 2 x 3 ( x 2 − 1 ) 2 dx = ...

  1. 1 third open parentheses straight x squared minus 1 close parentheses cubed plus 1 fourth open parentheses straight x squared minus 1 close parentheses squared plus straight C

  2. 1 third open parentheses straight x squared minus 1 close parentheses cubed plus 1 fourth open parentheses straight x squared minus 1 close parentheses to the power of 4 plus straight C

  3. 1 third open parentheses straight x squared minus 1 close parentheses cubed plus 1 fourth open parentheses straight x squared plus 1 close parentheses to the power of 4 plus straight C

  4. 1 third open parentheses straight x squared plus 1 close parentheses cubed plus 1 fourth open parentheses straight x squared plus 1 close parentheses to the power of 4 plus straight C

  5. 1 third open parentheses straight x squared minus 1 close parentheses to the power of 4 plus 1 fourth open parentheses straight x squared minus 1 close parentheses cubed plus straight C

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Misalkan Soal diatas menjadi

Misalkan  straight U equals straight x squared minus 1

Soal diatas menjadi integral straight x squared open parentheses straight x squared minus 1 close parentheses 2 xdx equals integral open parentheses straight u plus 1 close parentheses straight u squared du equals 1 fourth straight u to the power of 4 plus 1 third straight u cubed plus straight c

Jadi space integral 2 x cubed left parenthesis x squared minus 1 right parenthesis squared space d x equals 1 fourth left parenthesis x squared minus 1 right parenthesis to the power of 4 plus 1 third left parenthesis x squared minus 1 right parenthesis cubed plus C  

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