Pertanyaan

x → ∞ lim 4 x 2 − x + 7 − ( 2 x + 1 ) =

$x \to \infty lim 4 x^{2} - x + 7 - (2 x + 1) =$

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

Klaim

N. Mustikowati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as straight x rightwards arrow infinity of square root of ax squared plus bx plus straight c end root minus square root of px squared plus qx plus straight r end root end cell row straight a equals cell straight p rightwards double arrow fraction numerator straight b minus straight q over denominator 2 square root of straight a end fraction end cell row blank blank blank row blank blank cell limit as straight x rightwards arrow infinity of square root of 4 straight x squared minus straight x plus 7 end root minus left parenthesis 2 straight x plus 1 right parenthesis end cell row blank equals cell limit as straight x rightwards arrow infinity of square root of 4 straight x squared minus straight x plus 7 end root minus square root of left parenthesis 2 straight x plus 1 right parenthesis squared end root end cell row blank equals cell limit as straight x rightwards arrow infinity of square root of 4 straight x squared minus straight x plus 7 end root minus square root of 4 straight x squared plus 4 straight x plus 1 end root end cell row blank equals cell fraction numerator straight b minus straight q over denominator 2 square root of straight a end fraction end cell row blank equals cell fraction numerator negative 1 minus 4 over denominator 2 square root of 4 end fraction end cell row blank equals cell fraction numerator negative 5 over denominator 2 times 2 end fraction end cell row blank equals cell negative 5 over 4 end cell end table end style$