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⎝ ⎛ ​ 8 p − 3 2 ​ q − 1 4 1 ​ 27 p 2 3 1 ​ q 1 4 3 ​ ​ ⎠ ⎞ ​ 3 1 ​ = ....

 

  1. p q 

  2. 1 comma 5 p q 

  3. 3 p q 

  4. 1 comma 5 p squared q squared 

  5. 2 comma 25 p squared q squared 

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N. Puspita

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Jawaban terverifikasi

Jawaban

jawaban yang benar adalah B.

jawaban yang benar adalah B.

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Jika diberikanbilangan riil , danbilangan rasional maka berlaku sifatberikut. Sehingga dapat ditentukan hasil dari bentuk berikut. Sehingga diperoleh . Jadi, jawaban yang benar adalah B.

Jika diberikan bilangan riil a space dan space bb not equal to 0 dan bilangan rasional p comma space q comma space r maka berlaku sifat berikut.

table attributes columnalign right center left columnspacing 0px end attributes row cell b to the power of p over b to the power of q end cell equals cell b to the power of p minus q end exponent end cell row cell open parentheses a to the power of p close parentheses to the power of q end cell equals cell a to the power of p q end exponent end cell row cell open parentheses a to the power of p over b to the power of p close parentheses to the power of r end cell equals cell a to the power of p r end exponent over b to the power of q r end exponent end cell end table

Sehingga dapat ditentukan hasil dari bentuk berikut. 

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator 27 p to the power of 2 begin display style 1 third end style end exponent q to the power of 1 begin display style 3 over 4 end style end exponent over denominator 8 p to the power of negative begin display style 2 over 3 end style end exponent q to the power of negative 1 begin display style 1 fourth end style end exponent end fraction close parentheses to the power of 1 third end exponent end cell equals cell open parentheses fraction numerator 3 cubed p to the power of begin display style 7 over 3 end style end exponent q to the power of begin display style 7 over 4 end style end exponent over denominator 2 cubed p to the power of negative begin display style 2 over 3 end style end exponent q to the power of negative 1 begin display style 1 fourth end style end exponent end fraction close parentheses to the power of 1 third end exponent end cell row blank equals cell fraction numerator 3 to the power of 3 times begin display style 1 third end style end exponent p to the power of begin display style 7 over 3 times 1 third end style end exponent q to the power of begin display style 7 over 4 times 1 third end style end exponent over denominator 2 to the power of 3 times begin display style 1 third end style end exponent p to the power of negative begin display style 2 over 3 times 1 third end style end exponent q to the power of negative begin display style 5 over 4 times 1 third end style end exponent end fraction end cell row blank equals cell fraction numerator 3 p to the power of begin display style 7 over 9 end style end exponent q to the power of begin display style 7 over 12 end style end exponent over denominator 2 p to the power of negative begin display style 2 over 9 end style end exponent q to the power of negative begin display style 5 over 12 end style end exponent end fraction end cell row blank equals cell 3 over 2 p to the power of 7 over 9 minus open parentheses negative 2 over 9 close parentheses end exponent q to the power of 7 over 12 minus open parentheses negative 5 over 12 close parentheses end exponent end cell row blank equals cell 1 comma 5 p to the power of 7 over 9 plus 2 over 9 end exponent q to the power of 7 over 12 plus 5 over 12 end exponent end cell row blank equals cell 1 comma 5 p to the power of 9 over 9 end exponent q to the power of 12 over 12 end exponent end cell row blank equals cell 1 comma 5 p q end cell end table  

Sehingga diperoleh Error converting from MathML to accessible text..

Jadi, jawaban yang benar adalah B.

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