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S u k u k e − n d a r i s u a t u d ere t g eo m e t r i t ak hin gg a a d a l ah 5 − n . J u m l ah d ere t g eo m e t r i t ak hin gg a t erse b u t a d a l ah ...

  1. 1 fourth

  2. 1 fifth

  3. 1 over 6

  4. 1 over 7

  5. 1 over 8

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M. Nizar

Master Teacher

Mahasiswa/Alumni Universitas Siliwangi

Jawaban terverifikasi

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Pembahasan

U subscript n equals 5 to the power of negative n end exponent comma space m a k a space a equals U subscript 1 equals 5 to the power of negative 1 end exponent equals 1 fifth semicolon space U subscript 2 equals 5 to the power of negative 2 end exponent equals 1 over 5 squared equals 1 over 25 r equals U subscript 2 over U subscript 1 equals fraction numerator 1 over 25 over denominator 1 fifth end fraction equals 1 over 25 cross times 5 over 1 equals 1 fifth S e h i n g g a space j u m l a h space d e r e t n y a space a d a l a h S subscript infinity equals fraction numerator a over denominator 1 minus r end fraction equals fraction numerator 1 fifth over denominator 1 minus 1 fifth end fraction equals fraction numerator 1 fifth over denominator 4 over 5 end fraction equals 1 fifth cross times 5 over 4 equals 1 fourth

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Jumlah deret geometri 16 − 8 + 4 − 2 + ⋯ + 16 ( − 2 1 ​ ) n − 1 untuk jumlah n tak hingga adalah . . .

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