Roboguru

5,8 gram  direaksikan dengan larutan HCl 0,1 M. Tentukan volume larutan HCI yang bereaksi (  Mg = 24, H = 1, O = 16)

Pertanyaan

5,8 gram begin mathsize 14px style Mg open parentheses O H close parentheses subscript 2 end style direaksikan dengan larutan HCl 0,1 M. Tentukan volume larutan HCI yang bereaksi (undefined  Mg = 24, H = 1, O = 16)

Pembahasan Soal:

Larutan HCl 0,1 M artinya terdapat 0,1 mol dalam 1 L pelarut, sehingga volume larutan HCI adalah 1 L.

Jadi, volume larutan HCI adalah 1 L.

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

A. Chandra

Mahasiswa/Alumni Universitas Negeri Jakarta

Terakhir diupdate 30 Maret 2021

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Pembahasan Soal:

Diketahui:

begin mathsize 14px style italic A subscript r end style Na = 23, S = 32, O = 16, K = 39, Cl = 35,5, Ca = 40, H = 1, C = 12, Mn = 55, Cr = 52, Al = 27 

Pada soal diminta untuk melengkapi massa dan molaritas senyawa, sehingga:

A. begin mathsize 14px style Na subscript 2 S O subscript 4 end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r subscript Na subscript 2 S O subscript 4 end subscript end subscript end cell equals cell left parenthesis 2 cross times italic A subscript r space Na right parenthesis plus left parenthesis 1 cross times italic A subscript r space S right parenthesis plus left parenthesis 4 cross times italic A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 2 cross times 23 right parenthesis plus left parenthesis 1 cross times 32 right parenthesis plus left parenthesis 4 cross times 16 right parenthesis end cell row blank equals cell 46 plus 32 plus 64 end cell row blank equals cell 142 space g space mol to the power of negative sign 1 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Na subscript 2 S O subscript 4 end subscript end cell equals cell m over italic M subscript r end cell row blank equals cell fraction numerator 0 comma 71 over denominator 142 end fraction end cell row blank equals cell 0 comma 005 space mol end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets Na subscript 2 S O subscript 4 close square brackets end cell equals cell n over V end cell row blank equals cell fraction numerator 0 comma 005 over denominator 0 comma 05 end fraction end cell row blank equals cell 0 comma 1 space M end cell end table end style 

B. KCl

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r subscript KCl end subscript end cell equals cell left parenthesis 1 cross times italic A subscript r space K right parenthesis plus left parenthesis 1 cross times italic A subscript r space Cl right parenthesis end cell row blank equals cell left parenthesis 1 cross times 39 right parenthesis plus left parenthesis 1 cross times 35 comma 5 right parenthesis end cell row blank equals cell 39 plus 35 comma 5 end cell row blank equals cell 74 comma 5 space g space mol to the power of negative sign 1 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript KCl end cell equals cell m over italic M subscript r end cell row blank equals cell fraction numerator 1 comma 49 over denominator 74 comma 5 end fraction end cell row blank equals cell 0 comma 02 space mol end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets K Cl close square brackets end cell equals cell n over V end cell row blank equals cell fraction numerator 0 comma 02 over denominator 0 comma 1 end fraction end cell row blank equals cell 0 comma 2 space M end cell end table end style 

C. begin mathsize 14px style Ca open parentheses O H close parentheses subscript 2 end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r subscript Ca open parentheses O H close parentheses subscript 2 end subscript end subscript end cell equals cell left parenthesis 1 cross times italic A subscript r space Ca right parenthesis plus left parenthesis 2 cross times italic A subscript r space O right parenthesis plus left parenthesis 2 cross times italic A subscript r space H right parenthesis end cell row blank equals cell left parenthesis 1 cross times 40 right parenthesis plus left parenthesis 2 cross times 16 right parenthesis plus left parenthesis 2 cross times 1 right parenthesis end cell row blank equals cell 40 plus 32 plus 2 end cell row blank equals cell 74 space g space mol to the power of negative sign 1 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Ca open parentheses O H close parentheses subscript 2 end subscript end cell equals cell m over italic M subscript r end cell row blank equals cell fraction numerator 3 comma 7 over denominator 74 end fraction end cell row blank equals cell 0 comma 05 space mol end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell left square bracket Ca open parentheses O H close parentheses subscript 2 right square bracket end cell equals cell n over V end cell row blank equals cell fraction numerator 0 comma 05 over denominator 0 comma 25 end fraction end cell row blank equals cell 0 comma 2 space M end cell end table end style 

D. begin mathsize 14px style H subscript 2 C subscript 2 O subscript 4 end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r subscript H subscript 2 C subscript 2 O subscript 4 end subscript end subscript end cell equals cell left parenthesis 2 cross times italic A subscript r space H right parenthesis plus left parenthesis 2 cross times italic A subscript r space C right parenthesis plus left parenthesis 4 cross times italic A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 2 cross times 1 right parenthesis plus left parenthesis 2 cross times 12 right parenthesis plus left parenthesis 4 cross times 16 right parenthesis end cell row blank equals cell 2 plus 24 plus 64 end cell row blank equals cell 90 space g space mol to the power of negative sign 1 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript H subscript 2 C subscript 2 O subscript 4 end subscript end cell equals cell m over italic M subscript r end cell row blank equals cell fraction numerator 18 comma 0 over denominator 90 end fraction end cell row blank equals cell 0 comma 2 space mol end cell end table end style 

 begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H subscript 2 C subscript 2 O subscript 4 close square brackets end cell equals cell n over V end cell row blank equals cell fraction numerator 0 comma 2 over denominator 0 comma 5 end fraction end cell row blank equals cell 0 comma 4 space M end cell end table end style 

E. begin mathsize 14px style Na subscript 2 S subscript 2 O subscript 3 end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r subscript Na subscript 2 S subscript 2 O subscript 3 end subscript end subscript end cell equals cell left parenthesis 2 cross times italic A subscript r space Na right parenthesis plus left parenthesis 2 cross times italic A subscript r space S right parenthesis plus left parenthesis 3 cross times italic A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 2 cross times 23 right parenthesis plus left parenthesis 2 cross times 32 right parenthesis plus left parenthesis 3 cross times 16 right parenthesis end cell row blank equals cell 46 plus 64 plus 48 end cell row blank equals cell 158 space g space mol to the power of negative sign 1 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Na subscript 2 S subscript 2 O subscript 3 end subscript end cell equals cell m over italic M subscript r end cell row blank equals cell fraction numerator 3 comma 95 over denominator 158 end fraction end cell row blank equals cell 0 comma 005 space mol end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets Na subscript 2 S subscript 2 O subscript 3 close square brackets end cell equals cell n over V end cell row blank equals cell fraction numerator 0 comma 005 over denominator 0 comma 1 end fraction end cell row blank equals cell 0 comma 05 space M end cell end table end style 

F. begin mathsize 14px style Ca Cl subscript 2 point 6 H subscript 2 O end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r subscript Ca Cl subscript 2 point 6 H subscript 2 O end subscript end subscript end cell equals cell left parenthesis 1 cross times italic A subscript r space Ca right parenthesis plus left parenthesis 2 cross times italic A subscript r space Cl right parenthesis plus left parenthesis 12 cross times italic A subscript r space H right parenthesis plus left parenthesis 6 cross times italic A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 1 cross times 40 right parenthesis plus left parenthesis 2 cross times 35 comma 5 right parenthesis plus left parenthesis 12 cross times 1 right parenthesis plus left parenthesis 6 cross times 16 right parenthesis end cell row blank equals cell 40 plus 71 plus 12 plus 96 end cell row blank equals cell 219 space g space mol to the power of negative sign 1 end exponent end cell end table end style  

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Ca Cl subscript 2 point 6 H subscript 2 O end subscript end cell equals cell M cross times V end cell row blank equals cell 0 comma 2 cross times 0 comma 2 end cell row blank equals cell 0 comma 04 space mol end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript Ca Cl subscript 2 point 6 H subscript 2 O end subscript end cell equals cell n cross times italic M subscript r end cell row blank equals cell 0 comma 04 cross times 219 end cell row blank equals cell 8 comma 76 space g end cell end table end style 

G. begin mathsize 14px style K Mn O subscript 4 end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r subscript K Mn O subscript 4 end subscript end subscript end cell equals cell left parenthesis 1 cross times italic A subscript r space K right parenthesis plus left parenthesis 1 cross times italic A subscript r space Mn right parenthesis plus left parenthesis 4 cross times italic A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 1 cross times 39 right parenthesis plus left parenthesis 1 cross times 55 right parenthesis plus left parenthesis 4 cross times 16 right parenthesis end cell row blank equals cell 39 plus 55 plus 64 end cell row blank equals cell 158 space g space mol to the power of negative sign 1 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript K Mn O subscript 4 end subscript end cell equals cell M cross times V end cell row blank equals cell 0 comma 1 cross times 0 comma 25 end cell row blank equals cell 0 comma 025 space mol end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript K Mn O subscript 4 end subscript end cell equals cell n cross times italic M subscript r end cell row blank equals cell 0 comma 025 cross times 158 end cell row blank equals cell 3 comma 95 space g end cell end table end style 

H. begin mathsize 14px style K subscript 2 Cr subscript 2 O subscript 7 end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r subscript K subscript 2 Cr subscript 2 O subscript 7 end subscript end subscript end cell equals cell left parenthesis 2 cross times italic A subscript r space K right parenthesis plus left parenthesis 2 cross times italic A subscript r space Cr right parenthesis plus left parenthesis 7 cross times italic A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 2 cross times 39 right parenthesis plus left parenthesis 2 cross times 52 right parenthesis plus left parenthesis 7 cross times 17 right parenthesis end cell row blank equals cell 78 plus 104 plus 112 end cell row blank equals cell 294 space g space mol to the power of negative sign 1 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript K subscript 2 Cr subscript 2 O subscript 7 end subscript end cell equals cell M cross times V end cell row blank equals cell 0 comma 5 cross times 0 comma 1 end cell row blank equals cell 0 comma 05 space mol end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript K subscript 2 Cr subscript 2 O subscript 7 end subscript end cell equals cell n cross times italic M subscript r end cell row blank equals cell 0 comma 05 cross times 294 end cell row blank equals cell 14 comma 7 space g end cell end table end style 

I. begin mathsize 14px style Al subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r subscript Al subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 end subscript end subscript end cell equals cell left parenthesis 2 cross times italic A subscript r space Al right parenthesis plus left parenthesis 3 cross times italic A subscript r space S right parenthesis plus left parenthesis 12 cross times italic A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 2 cross times 27 right parenthesis plus left parenthesis 3 cross times 32 right parenthesis plus left parenthesis 12 cross times 16 right parenthesis end cell row blank equals cell 54 plus 96 plus 192 end cell row blank equals cell 342 space g space mol to the power of negative sign 1 end exponent end cell end table end style  

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Al subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 end subscript end cell equals cell M cross times V end cell row blank equals cell 0 comma 2 cross times 0 comma 1 end cell row blank equals cell 0 comma 02 space mol end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript Al subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 end subscript end cell equals cell n cross times italic M subscript r end cell row blank equals cell 0 comma 02 cross times 342 end cell row blank equals cell 6 comma 84 space g end cell end table end style  

J. begin mathsize 14px style Na subscript 2 C O subscript 3 end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r subscript Na subscript 2 C O subscript 3 end subscript end subscript end cell equals cell left parenthesis 2 cross times italic A subscript r space Na right parenthesis plus left parenthesis 1 cross times italic A subscript r space C right parenthesis plus left parenthesis 3 cross times italic A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 2 cross times 23 right parenthesis plus left parenthesis 1 cross times 12 right parenthesis plus left parenthesis 3 cross times 16 right parenthesis end cell row blank equals cell 46 plus 12 plus 48 end cell row blank equals cell 106 space g space mol to the power of negative sign 1 end exponent end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Na subscript 2 C O subscript 3 end subscript end cell equals cell M cross times V end cell row blank equals cell 1 cross times 0 comma 01 end cell row blank equals cell 0 comma 01 space mol end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell m subscript Na subscript 2 C O subscript 3 end subscript end cell equals cell n cross times italic M subscript r end cell row blank equals cell 0 comma 01 cross times 106 end cell row blank equals cell 1 comma 06 space g end cell end table end style 

sehingga isi tabel yang lengkap menjadi:

 

Jadi, jawaban yang benar sesuai tabel diatas.

0

Roboguru

Di ketahui massa atom relative , maka massa 2 mol  adalah....

Pembahasan Soal:

Massa atom relatif dilambangakan dengan Ar merupakan massa suatu atom yang didapat dari rasio perbandingan standarnya.

Maka untuk menghitung massa 2 mol K subscript 2 C O subscript 3 dapat dilakukan melalui tahap berikut:

  • Menghitung Mr K subscript 2 C O subscript 3

table attributes columnalign right center left columnspacing 0px end attributes row cell Mr space K subscript 2 C O subscript 3 end cell equals cell left parenthesis 2 xAr space K right parenthesis plus left parenthesis 1 xAr space C right parenthesis plus left parenthesis 3 x space Ar space O right parenthesis end cell row blank equals cell left parenthesis 2 space x space 39 right parenthesis plus left parenthesis 1 space x space 12 right parenthesis plus left parenthesis 3 space x space 16 right parenthesis end cell row blank equals cell 78 plus 12 plus 48 end cell row blank equals cell 138 space begin inline style bevelled g over mol end style end cell end table

  • Menghitung massa

table attributes columnalign right center left columnspacing 0px end attributes row massa equals cell mol space x space Mr end cell row blank equals cell 2 space mol space x space 138 space begin inline style bevelled g over mol end style end cell row blank equals cell 276 space gram end cell end table
 

Jadi, jawaban yang tepat adalah C.space

0

Roboguru

Dalam 1 L larutan , setelah diukur pH-nya dengan pH-meter menunjukkan larutan tersebut mempunyai pH = 5. Berapakah massa yang terkandung dalam larutan itu?

Pembahasan Soal:

open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 adalah garam terhidrolisis asam, sehingga dapat diperoleh:

table attributes columnalign right center left columnspacing 0px end attributes row pH equals 5 row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 10 to the power of negative sign 5 end exponent end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of K subscript w over K subscript b cross times open square brackets open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 close square brackets end root end cell row cell 10 to the power of negative sign 5 end exponent end cell equals cell square root of 10 to the power of negative sign 14 end exponent over 10 to the power of negative sign 5 end exponent cross times open square brackets open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 close square brackets end root end cell row cell 10 to the power of negative sign 10 end exponent end cell equals cell 10 to the power of negative sign 9 end exponent cross times open square brackets open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 close square brackets end cell row cell begin bold style open square brackets open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 close square brackets end style end cell bold equals cell bold 0 bold comma bold 1 bold space italic M end cell end table


Massa garam dapat dihitung dengan cara:

table attributes columnalign right center left columnspacing 0px end attributes row cell n space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 end cell equals cell M cross times V end cell row cell n space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 end cell equals cell 0 comma 1 space M cross times 1 L end cell row cell n space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 end cell equals cell 0 comma 1 space mol end cell row cell massa space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 end cell equals cell n cross times M subscript r end cell row cell massa space open parentheses N H subscript 4 close parentheses subscript 2 S O subscript 4 end cell equals cell 0 comma 1 cross times 132 end cell row cell bold massa bold space begin bold style open parentheses N H subscript 4 close parentheses end style subscript bold 2 S O subscript bold 4 end cell bold equals cell bold 13 bold comma bold 2 bold space bold gram end cell end table


Jadi, massa garam yang terkandung dalam larutan itu adalah 13,2 gram.space

0

Roboguru

Natrium karbonat digunakan sebagai salah satu bahan untuk membuat kaca. Senyawa ini merupakan hasil reaksi dari garam dan kapur. Reaksi yang terjadi sebagai berikut:   Pada industri pembuatan natr...

Pembahasan Soal:

Reaksi yang terjadi pada industri pembuatan bahan kaca natrium karbonat adalah


begin mathsize 14px style 2 Na Cl space left parenthesis italic a italic q right parenthesis space plus space Ca C O subscript 3 space end subscript open parentheses italic s close parentheses space rightwards arrow space Na subscript 2 C O subscript 3 space left parenthesis italic a italic q right parenthesis space plus space Ca Cl subscript 2 space left parenthesis italic a italic q right parenthesis end style  

Garam yang bisa digunakan untuk membuat natrium karbonat adalah garam begin mathsize 14px style Na Cl end style. Sedangkan kapur dapat digunakan begin mathsize 14px style Ca C O subscript 3 end style.

begin mathsize 14px style Mr space Na Cl space space space space equals space left parenthesis 23 space plus space 35 comma 5 right parenthesis space g space mol to the power of negative sign 1 end exponent Mr space Na Cl space space space space equals space 58 comma 5 space g space mol to the power of negative sign 1 end exponent  Mr space Ca C O subscript 3 space equals left parenthesis space 40 space plus space 12 space plus space left parenthesis 3 cross times space 16 right parenthesis right parenthesis space g space mol to the power of negative sign 1 end exponent Mr space Ca C O subscript 3 space equals space 100 space g space mol to the power of negative sign 1 end exponent  Mr space Na subscript 2 C O subscript 3 equals space left parenthesis left parenthesis 2 cross times 23 right parenthesis space plus space 12 space plus space left parenthesis 3 cross times 16 right parenthesis right parenthesis space g space mol to the power of negative sign 1 end exponent Mr space Na subscript blank subscript 2 end subscript C O subscript 3 equals space 106 space g space mol to the power of negative sign 1 end exponent  mol space Na Cl space equals space massa over Mr mol space Na Cl space space equals space fraction numerator 234 space gr over denominator 58 comma 5 space g space mol to the power of negative sign 1 end exponent end fraction mol space Na Cl space equals 4 space mol  mol space Na subscript 2 C O subscript 3 space equals fraction numerator koefisien space Na subscript 2 C O subscript 3 over denominator Koefisien space Na Cl end fraction space cross times space mol space Na Cl mol space Na subscript 2 C O subscript 3 space equals 1 half cross times 4 space mol mol space Na subscript 2 C O subscript 3 space equals space 2 space mol  massa space Na subscript 2 C O subscript 3 space equals space 2 space mol space cross times 106 space g space mol to the power of negative sign 1 end exponent massa space Na subscript 2 C O subscript 3 space equals space 212 space gram  end style


Jadi, jawaban yang benar adalah C.

7

Roboguru

Konsentrasi larutan natrium nitrat,  yang dibuat dari melarutkan 1,7 gram kristal natrium nitrat ke dalam air hingga volume larutan 500 mL adalah ... (Na = 23, N = 14, O = 16)

Pembahasan Soal:

Kemolaran/molaritas (M) adalah salah satu satuan konsentrasi larutan yang menyatakan jumlah mol zat terlarut dalam 1 L larutan.

Penentuan kemolaran Na N O subscript 3 sebagai berikut.

1. Hitung Mr Na N O subscript 3:

table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r space Na N O subscript 3 end cell equals cell left parenthesis 1 cross times italic A subscript r space Na right parenthesis plus left parenthesis 1 cross times italic A subscript r space N right parenthesis plus left parenthesis 3 cross times italic A subscript r space O right parenthesis end cell row blank equals cell left parenthesis 1 cross times 23 right parenthesis plus left parenthesis 1 cross times 14 right parenthesis plus left parenthesis 3 cross times 16 right parenthesis end cell row blank equals cell 85 space g space mol to the power of negative sign 1 end exponent end cell end table 

2. Hitung mol Na N O subscript 3.

table attributes columnalign right center left columnspacing 0px end attributes row cell n subscript Na N O subscript 3 end subscript end cell equals cell m over italic M subscript r end cell row blank equals cell fraction numerator 1 comma 7 space g over denominator 85 space g forward slash mol end fraction end cell row blank equals cell 0 comma 02 space mol end cell end table  

3. Hitung konsentrasi Na N O subscript 3:

table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript Na N O subscript 3 end subscript end cell equals cell n over V end cell row blank equals cell fraction numerator 0 comma 02 space mol over denominator 0 comma 5 space L end fraction end cell row blank equals cell 0 comma 04 space M end cell end table  

Oleh karena itu, konsentrasi larutan Na N O subscript 3 adalah 0,04 M.

Jadi, jawaban yang benar adalah B.

0

Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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