Roboguru

344 gram gips mengandung 272 gram dan sisanya sebagai air hidrat. Tentukan rumus gips tersebut!

Pertanyaan

344 gram gips mengandung 272 gram Ca S O subscript 4 spacedan sisanya sebagai air hidrat. Tentukan rumus gips tersebut!

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell massa space sampel end cell equals cell 344 space g end cell row cell massa space Ca S O 4 end cell equals cell 272 space g end cell row cell massa space H subscript 2 O end cell equals cell 344 space g minus sign 272 space g equals 72 space g end cell row blank blank blank row cell Mr space Ca S O subscript 4 end cell equals cell Ar space Ca and Ar space S plus left parenthesis 4 xAr space O right parenthesis end cell row blank equals cell 40 plus 32 plus left parenthesis 4 x 16 right parenthesis end cell row blank equals cell 40 plus 32 plus 64 end cell row blank equals cell 136 space g forward slash mol end cell row blank blank blank row cell Mr space H subscript 2 O end cell equals cell left parenthesis 2 xAr space H right parenthesis plus Ar space O end cell row blank equals cell left parenthesis 2 x 1 right parenthesis plus 16 end cell row blank equals cell 2 plus 16 end cell row blank equals cell 18 space g forward slash mol end cell row blank blank blank row cell mol space Ca S O subscript 4 end cell equals cell fraction numerator massa space Ca S O subscript 4 over denominator Mr space Ca S O subscript 4 end fraction end cell row blank equals cell fraction numerator 272 space g over denominator 136 space g forward slash mol end fraction end cell row blank equals cell 2 space mol end cell row blank blank blank row cell mol space H subscript 2 O end cell equals cell fraction numerator massa space H subscript 2 O over denominator Mr space H subscript 2 O end fraction end cell row blank equals cell fraction numerator 72 space g over denominator 18 space g forward slash mol end fraction end cell row blank equals cell 4 space mol end cell row blank blank blank row blank blank cell mol space Ca S O subscript 4 space colon space bold mol bold space H subscript bold 2 O end cell row blank blank cell 2 space mol colon 4 space mol end cell row blank blank cell 1 colon 2 end cell row blank blank blank row cell bold mol bold space H subscript bold 2 O end cell bold equals cell bold 2 bold mol end cell row cell bold rumus bold space bold gips end cell bold equals cell Ca S O subscript bold 4 bold point bold 2 H subscript bold 2 O end cell row blank blank blank end table

Jadi, rumus gips tersebut adalah Ca S O subscript 4 point 2 H subscript 2 O.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 Juni 2021

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved