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​​​Di antara senyawa berikut yang memiliki massa molekul relatif sebesar 120 adalah .... ( A r ​ O = 16, Mg = 24, Al = 27, P = 31, S = 32, Cl = 35,5, Ca = 40, Fe = 56 )

​​​Di antara senyawa berikut yang memiliki massa molekul relatif sebesar 120 adalah ....  O = 16, Mg = 24, Al = 27, P = 31, S = 32, Cl = 35,5, Ca = 40, Fe = 56 

  1. begin mathsize 14px style Fe Cl subscript 3 end style 

  2. begin mathsize 14px style Al P O subscript 4 end style 

  3. begin mathsize 14px style Mg S O subscript 4 end style 

  4. begin mathsize 14px style Ca S O subscript 4 end style 

  5. begin mathsize 14px style Al subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 end style 

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Jawaban terverifikasi

Jawaban

jawaban yang benar adalah C.

jawaban yang benar adalah C.

Pembahasan

Massa molekul relatif dapat ditentukan dengan menggunakan persamaan berikut. 1. 2. 3. 4. 5. Jadi, jawaban yang benar adalah C.

Massa molekul relatif dapat ditentukan dengan menggunakan persamaan berikut.

1. italic M subscript italic r bold space Fe Cl subscript bold 3 
 

table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r space Fe Cl subscript 3 end cell equals cell left parenthesis 1 cross times italic A subscript r space Fe right parenthesis plus left parenthesis 3 cross times italic A subscript r space Cl right parenthesis end cell row cell italic M subscript r space Fe Cl subscript 3 end cell equals cell left parenthesis 1 cross times 56 right parenthesis plus left parenthesis 3 cross times 35 comma 5 right parenthesis end cell row cell italic M subscript r space Fe Cl subscript 3 end cell equals cell 56 plus 106 comma 5 end cell row cell italic M subscript r space Fe Cl subscript 3 end cell equals cell 162 comma 5 end cell end table 
 

2. italic M subscript italic r bold space Al P O subscript bold 4
 

 table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript italic r space Al P O subscript italic 4 end cell equals cell left parenthesis 1 cross times italic A subscript r space Al right parenthesis plus left parenthesis 1 cross times italic A subscript r space P right parenthesis plus left parenthesis 4 cross times italic A subscript r space O right parenthesis end cell row cell italic M subscript italic r space Al P O subscript italic 4 end cell equals cell left parenthesis 1 cross times 27 right parenthesis plus left parenthesis 1 cross times 31 right parenthesis plus left parenthesis 4 cross times 16 right parenthesis end cell row cell italic M subscript r space Al P O subscript 4 end cell equals cell 27 plus 31 plus 64 end cell row cell italic M subscript r space Al P O subscript 4 end cell equals 122 end table 
 

3. italic M subscript italic r bold space Mg S O subscript bold 4 
 

table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r space Mg S O subscript 4 end cell equals cell left parenthesis 1 cross times italic A subscript r space Mg right parenthesis plus left parenthesis 1 cross times italic A subscript r space S right parenthesis plus left parenthesis 4 cross times italic A subscript r space O right parenthesis end cell row cell italic M subscript r space Mg S O subscript 4 end cell equals cell left parenthesis 1 cross times 24 right parenthesis plus left parenthesis 1 cross times 32 right parenthesis plus left parenthesis 4 cross times 16 right parenthesis end cell row cell italic M subscript r space Mg S O subscript 4 end cell equals cell 24 plus 32 plus 64 space end cell row cell italic M subscript r space Mg S O subscript 4 end cell equals 120 end table    
 

4. italic M subscript italic r bold space Ca S O subscript bold 4  
 

table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r space Ca S O subscript 4 end cell equals cell left parenthesis 1 cross times italic A subscript r space Ca right parenthesis plus left parenthesis 1 cross times italic A subscript r space S right parenthesis plus left parenthesis 4 cross times italic A subscript r space O right parenthesis end cell row cell italic M subscript r space Ca S O subscript 4 end cell equals cell left parenthesis 1 cross times 40 right parenthesis plus left parenthesis 1 cross times 32 right parenthesis plus left parenthesis 4 cross times 16 right parenthesis end cell row cell italic M subscript r space Ca S O subscript 4 end cell equals cell 40 plus 32 plus 64 space end cell row cell italic M subscript r space Ca S O subscript 4 end cell equals 136 end table 
 

5. italic M subscript italic r bold space Al subscript bold 2 bold open parentheses S O subscript bold 4 bold close parentheses subscript bold 3 
 

table attributes columnalign right center left columnspacing 0px end attributes row cell italic M subscript r space Ca S O subscript 4 end cell equals cell left parenthesis 2 cross times italic A subscript r space Al right parenthesis plus left parenthesis 3 cross times italic A subscript r space S right parenthesis plus left parenthesis 12 cross times italic A subscript r space O right parenthesis end cell row cell italic M subscript r space Ca S O subscript 4 end cell equals cell left parenthesis 2 cross times 27 right parenthesis plus left parenthesis 3 cross times 32 right parenthesis plus left parenthesis 12 cross times 16 right parenthesis end cell row cell italic M subscript r space Ca S O subscript 4 end cell equals cell 54 plus 96 plus 192 end cell row cell italic M subscript r space Ca S O subscript 4 end cell equals 342 end table 
 

Jadi, jawaban yang benar adalah C.

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