Iklan

Pertanyaan

tan 2 1 ​ p = ....

....

  1. begin mathsize 14px style plus-or-minus square root of fraction numerator 1 plus cos invisible function application p over denominator 1 minus cos invisible function application p end fraction end root end style  

  2. begin mathsize 14px style plus-or-minus square root of fraction numerator sin invisible function application p over denominator 1 plus cos invisible function application p end fraction end root end style  

  3. begin mathsize 14px style plus-or-minus fraction numerator sin invisible function application p over denominator 1 plus cos invisible function application p end fraction end style  

  4. begin mathsize 14px style plus-or-minus fraction numerator 1 plus cos invisible function application p over denominator sin invisible function application p end fraction end style  

  5. begin mathsize 14px style plus-or-minus fraction numerator sin invisible function application p over denominator 1 minus cos invisible function application p end fraction end style  

Ikuti Tryout SNBT & Menangkan E-Wallet 100rb

Habis dalam

02

:

17

:

05

:

48

Klaim

Iklan

D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

Ingat bahwa Sehingga Maka pilihan yang benar adalah C.

Ingat bahwa

begin mathsize 14px style tan invisible function application 1 half A equals plus-or-minus square root of fraction numerator 1 minus cos invisible function application A over denominator 1 plus cos invisible function application A end fraction end root tan invisible function application 1 half A equals plus-or-minus fraction numerator sin invisible function application A over denominator 1 plus cos invisible function application A end fraction tan invisible function application 1 half A equals plus-or-minus fraction numerator 1 minus cos invisible function application A over denominator sin invisible function application A end fraction end style

Sehingga

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell tan invisible function application 1 half p end cell equals cell plus-or-minus square root of fraction numerator 1 minus cos invisible function application p over denominator 1 plus cos invisible function application p end fraction end root end cell row cell tan invisible function application 1 half p end cell equals cell plus-or-minus fraction numerator sin invisible function application p over denominator 1 plus cos invisible function application p end fraction end cell row cell tan invisible function application 1 half p end cell equals cell plus-or-minus fraction numerator 1 minus cos invisible function application p over denominator sin invisible function application p end fraction end cell end table end style

Maka pilihan yang benar adalah C.

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

3

Iklan

Pertanyaan serupa

Jika cos A 1 − sin A ​ = p , maka nilai dari tan 2 1 ​ A adalah ....

1

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia