Roboguru

,

Grafik space fungsi space straight f left parenthesis straight x right parenthesis equals negative 2 straight x comma space dengan space domain space dan space kodomainnya space bilangan space real space adalah space....,

Jawaban:

straight f open parentheses straight x close parentheses equals negative 2 straight x comma space maka space straight m equals negative 2,

Mencari space gradien space left parenthesis straight m right parenthesis space dapat space dicari space dengan space rumus colon  m equals fraction numerator increment y over denominator increment x end fraction equals fraction numerator y subscript 2 minus y subscript 1 over denominator x subscript 2 minus x subscript 1 end fraction  straight A. space straight m equals fraction numerator 1 minus open parentheses negative 1 close parentheses over denominator negative 2 minus 2 end fraction equals fraction numerator 2 over denominator negative 4 end fraction equals negative 1 half  straight B. space straight m equals fraction numerator 2 minus open parentheses negative 1 close parentheses over denominator 4 minus open parentheses negative 1 close parentheses end fraction equals 3 over 5  straight C. space straight m equals fraction numerator 4 minus open parentheses negative 4 close parentheses over denominator negative 2 minus 2 end fraction equals fraction numerator 8 over denominator negative 4 end fraction equals negative 2  straight D. space straight m equals fraction numerator 4 minus open parentheses negative 4 close parentheses over denominator 2 minus open parentheses negative 2 close parentheses end fraction equals 8 over 4 equals 2

0

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved