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Pertanyaan

x → ∞ lim ​ 5 x 4 − 2 x 3 + 1 ​ − 5 x 4 + 8 x 2 + 7 ​ 16 x 2 − 8 x − 15 ​ − 16 x 2 + 8 x + 5 ​ ​ = ...

...

  1. 0

  2. 1 fifth square root of 5

  3. negative 1 fifth square root of 5

  4. 2 over 5 square root of 5

  5. negative 2 over 5 square root of 5

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H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

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Pembahasan

limit as x rightwards arrow infinity of space fraction numerator square root of 16 x squared minus 8 x minus 15 end root minus square root of 16 x squared plus 8 x plus 5 end root over denominator square root of 5 x to the power of 4 minus 2 x cubed plus 1 end root minus square root of 5 x to the power of 4 plus 8 x squared plus space 7 end root end fraction equals space fraction numerator limit as x rightwards arrow infinity of open parentheses square root of 16 x squared minus 8 x minus 15 end root minus square root of 16 x squared plus 8 x plus 5 end root close parentheses over denominator limit as x rightwards arrow infinity of open parentheses square root of 5 x to the power of 4 minus 2 x cubed plus 1 end root minus square root of 5 x to the power of 4 plus 8 x squared plus space 7 end root close parentheses end fraction equals space fraction numerator begin display style fraction numerator negative 8 minus 8 over denominator 2 square root of 16 end fraction end style over denominator begin display style fraction numerator negative 2 minus 8 over denominator 2 square root of 5 end fraction end style end fraction space equals space fraction numerator negative 2 over denominator negative square root of 5 end fraction space equals space 2 over 5 square root of 5

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x → ∞ lim ​ ( 2 x − 2 ) 2 3 8 x 3 − 2 x 2 + 7 ​ 16 x 2 − 4 x + 5 ​ ​ = ...

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