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7 1 ​ × 13 3 ​ − 13 3 ​ × 21 1 ​ = ....

....

  1. size 14px 2 over size 14px 17   

  2. size 14px 2 over size 14px 91   

  3. size 14px 4 over size 14px 17   

  4. size 14px 4 over size 14px 91   

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I. Sutiawan

Master Teacher

Mahasiswa/Alumni Universitas Pasundan

Jawaban terverifikasi

Pembahasan

Berdasarkan sifat-sifat pada operasi hitung pecahan, maka

Berdasarkan sifat-sifat pada operasi hitung pecahan, maka

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 1 over 7 cross times 3 over 13 minus 3 over 13 cross times 1 over 21 end cell equals cell 3 over 13 cross times 1 over 7 minus 3 over 13 cross times 1 over 21 end cell row blank equals cell 3 over 13 cross times open parentheses 1 over 7 minus 1 over 21 close parentheses end cell row blank equals cell 3 over 13 cross times open parentheses 1 over 7 cross times 3 over 3 minus 1 over 21 close parentheses end cell row blank equals cell 3 over 13 cross times open parentheses 3 over 21 minus 1 over 21 close parentheses end cell row blank equals cell 3 over 13 cross times 2 over 21 end cell row blank equals cell fraction numerator 3 cross times 2 over denominator 13 cross times 21 end fraction end cell row blank equals cell fraction numerator 3 cross times 2 over denominator 13 cross times open parentheses 3 cross times 7 close parentheses end fraction end cell row blank equals cell fraction numerator 2 over denominator 13 cross times 7 end fraction end cell row blank equals cell 2 over 91 end cell end table end style    

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2 + 3 + 4 3 ​ 2 ​ 1 ​ = ....

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