Pertanyaan

x → ∞ lim ( 2 x − 1 ) 2 3 27 x 3 − 16 x 2 + 5 25 x 2 − 4 x + 5 + 3 64 x 3 − 12 x 2 + 5 16 x 2 − 4 x + 5 = ...

$x \to \infty lim \frac{3 27 x ^{3} - 16 x ^{2} + 5 25 x ^{2} - 4 x + 5 + 3 64 x ^{3} - 12 x ^{2} + 5 16 x ^{2} - 4 x + 5}{( 2 x - 1 ) ^{2}} =$ ...

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Klaim

H. Nufus

Master Teacher

Mahasiswa/Alumni Universitas Negeri Surabaya

Jawaban terverifikasi

Pembahasan

$limit as x rightwards arrow infinity of space fraction numerator cube root of 27 x cubed minus 16 x squared plus 5 end root square root of 25 x squared minus 4 x plus 5 end root plus cube root of 64 x cubed minus 12 x squared plus 5 end root square root of 16 x squared minus 4 x plus 5 end root over denominator open parentheses 2 x minus 1 close parentheses squared end fraction limit as x rightwards arrow infinity of space fraction numerator cube root of 27 x cubed end root square root of 25 x squared end root plus cube root of 64 x cubed end root square root of 16 x squared end root over denominator open parentheses 2 x close parentheses squared end fraction limit as x rightwards arrow infinity of space fraction numerator open parentheses 3 x close parentheses open parentheses 5 x close parentheses plus open parentheses 4 x close parentheses open parentheses 4 x close parentheses over denominator 4 x squared end fraction space equals space fraction numerator 15 plus 16 over denominator 4 end fraction space equals space 31 over 4$