Tolong dong kakk

Garis k : 3x - 2y + 6 = 0 y = mx + c 3x - 2y + 6 = 0 ----> 2y = 3x + 6 y = (3/2)x + (6/2) y = (3/2)x + 3 m1 = 3/2 m1 × m2 = -1 (gradien tegak lurus) (3/2) × m2 = -1 m2 = -(2/3) A) 2x - 3y + 6 = 0 ----> 3y = 2x + 6 y = (2/3)x + (6/3) y = (2/3)x + 2 m2 = 2/3 ( tidak memenuhi) B) 2y + 3x + 6 = 0 ----> -2y = 3x + 6 y = (3/-2)x + (6/-2) y = -(3/2)x - 3 m2 = -3/2 ( tidak memenuhi) C) 2x + 3y - 6 = 0 ----> 3y = -2x + 6 y = (-2/3)x + (6/3) y = -(2/3)x + 2 m2 = -2/3 (memenuhi) D) 3y -2x - 6 = 0 ----> 3y = 2x + 6 y = (2/3)x + (6/3) y = (2/3)x + 2 m2 = 2/3 ( tidak memenuhi) Persamaan garis yang tegak lurus dengan garis k adalah 2x + 3y - 6 = 0 (c)