Tolong dijawab ya kak...

Dik : f(x) = x-3, g(x) = 3/x, x≠0 Jawaban A f ○ g (x) = 3/x - 3 = (3-3x)/3 Invers: y = (3-3x)/3 yx+3x = 3 x (y+3) = 3 x = 3/(y+3) (f ○ g)^-1 (x) = 3/(x+3) Syarat : x+3 ≠ 0 x ≠ 0-3 x ≠ -3 g(x) = 3/x Invers : y = 3/x yx = 3 x = 3/y g^-1 (x) = 3/x f(x) = x-3 Invers : y = x-3 y+3 = x f^-1 (x) = x+3 (g^-1 ○ f^-1) (x) = 3/(x+3) (f ○ g)^-1 (x) = (g^-1 ○ f^-1) (x) 3/(x+3) = 3/(x+3) Jadi, (f ○ g)^-1 (x) = (g^-1 ○ f^-1) (x) Jawaban B f(x) = x-3 Invers : y = x-3 y+3 = x f^-1 (x) = x+3 f ○ f^-1 ○ f (1) = f ○ f^-1 (1-3) f ○ f^-1 ○ f (1) = f ○ f^-1 (-2) f ○ f^-1 ○ f (1) = f ((-2)+3) f ○ f^-1 ○ f (1) = f (1) f ○ f^-1 ○ f (1) = 1-3 f ○ f^-1 ○ f (1) = -2