Grecia G

21 Juli 2023 10:16

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Grecia G

21 Juli 2023 10:16

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Jawaban terverifikasi

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Testa T

Level 100

21 Juli 2023 10:25

Jawaban terverifikasi

<p><strong>Bagian a</strong></p><p>y³ × 2y⁷ × (3y)² = 2y¹⁰ × 3²y²</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 2y¹⁰ × 9y²</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;= 18y¹²</p><p><strong>Bagian b</strong></p><p>b × 2y⁷ × b³ × y² = b⁴ × 2y⁹</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 2b⁴y⁹</p><p><strong>Bagian c</strong></p><p>3m³ × (mn)⁴ = 3m³ × m⁴n⁴</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 3n⁴m⁷</p><p><strong>Bagian d</strong></p><p>(tn³)⁴ × 4t³ = t⁴n¹² × 4t³</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = 4n¹²t⁷</p><p>&nbsp;</p><p>~Semoga membantu</p><p>~Maaf kalau salah</p>

Bagian a

y³ × 2y⁷ × (3y)² = 2y¹⁰ × 3²y²

                           = 2y¹⁰ × 9y²

                           = 18y¹²

Bagian b

b × 2y⁷ × b³ × y² = b⁴ × 2y⁹

                            = 2b⁴y⁹

Bagian c

3m³ × (mn)⁴ = 3m³ × m⁴n⁴

                      = 3n⁴m⁷

Bagian d

(tn³)⁴ × 4t³ = t⁴n¹² × 4t³

                    = 4n¹²t⁷

 

~Semoga membantu

~Maaf kalau salah


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Dela A

Community

Level 88

22 Juli 2023 11:44

Jawaban terverifikasi

<p>Menyederhanakan aljabar.</p><p>a) y³ × 2y⁷ × (3y)²</p><p>= y³ × 2y⁷ × 3²y²</p><p>= y³ × 2y⁷ × 9y²</p><p>= (2 × 9) × y³ × y⁷ × y²</p><p>= 18 × y^(3 + 7 + 2)</p><p>Catatan <strong>y^x artinya y pangkat x</strong></p><p>= 18 × y¹²</p><p>= <strong>18y¹²</strong></p><p>&nbsp;</p><p>b) b × 2y⁷ × b³ × y²</p><p>= b × b³ × 2y⁷ × y²</p><p>= b^(1 + 3) × 2 × y^(7+2)</p><p>= b⁴ × 2 × y⁹</p><p>= <strong>2b⁴y⁹</strong></p><p>&nbsp;</p><p>c) 3m³ × (mn)⁴</p><p>= 3m³ × m⁴n⁴</p><p>= 3 × m^(3+4) × n⁴</p><p>= 3 × m⁷ × n⁴</p><p>= <strong>3m⁷n⁴</strong></p><p>&nbsp;</p><p>d) (tn³)⁴ × 4t³</p><p>= t^(1×4) × n^(3×4) × 4 × t³</p><p>= t⁴ × n¹² × 4 × t³</p><p>= 4 × t⁴ × t³ × n¹²</p><p>= 4 × t^(4+3) × n¹²</p><p>= 4 × t⁷ × n¹²</p><p>= <strong>4n¹²t⁷</strong></p><p>&nbsp;</p>

Menyederhanakan aljabar.

a) y³ × 2y⁷ × (3y)²

= y³ × 2y⁷ × 3²y²

= y³ × 2y⁷ × 9y²

= (2 × 9) × y³ × y⁷ × y²

= 18 × y^(3 + 7 + 2)

Catatan y^x artinya y pangkat x

= 18 × y¹²

= 18y¹²

 

b) b × 2y⁷ × b³ × y²

= b × b³ × 2y⁷ × y²

= b^(1 + 3) × 2 × y^(7+2)

= b⁴ × 2 × y⁹

= 2b⁴y⁹

 

c) 3m³ × (mn)⁴

= 3m³ × m⁴n⁴

= 3 × m^(3+4) × n⁴

= 3 × m⁷ × n⁴

= 3m⁷n⁴

 

d) (tn³)⁴ × 4t³

= t^(1×4) × n^(3×4) × 4 × t³

= t⁴ × n¹² × 4 × t³

= 4 × t⁴ × t³ × n¹²

= 4 × t^(4+3) × n¹²

= 4 × t⁷ × n¹²

= 4n¹²t⁷

 


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