Tolong bisa dibantukah?

<p>Jawaban: (16 a² . c⁴)/b²<br><br>ingat!</p><p>a^m : aⁿ = a^m-n</p><p>(a^m)ⁿ = a^mxn</p><p>a^-m = 1/a^m<br><br>Asumsikan soal [(4a^-2/3 . b^-5/4 . c^-6/5)/(16a^1/3 . b^-9/4 . c^4/5)]^-2</p><p>= [(4a^-2/3 . b^-5/4 . c^-6/5)/(16a^1/3 . b^-9/4 . c^4/5)]^-2<br>= [4/16 . a^-2/3-1/3 . b^-5/4-(-9/4) . c^-6/5-4/5]^-2</p><p>= [1/4 . a^-3/3 . b^4/4 . c^-10/5]^-2</p><p>= [1/4 . a^-1 . b¹ . c^-2]^-2</p><p>= [1^-2/4^-2 . a² . b^-2 . c⁴]</p><p>= [4² . a² . c⁴]/b²</p><p>= (16 a² . c⁴)/b²</p><p>&nbsp;</p><p>Jadi, jawabanya adalah (16 a² . c⁴)/b²</p>