tolong beserta caranya

<p>Jawaban &nbsp;<strong>ΔH reaksi = -163,2 kJ</strong></p><p>&nbsp;</p><p><strong>Pembahasan&nbsp;</strong></p><p>Reaksi yg terjadi:</p><p>N2H4 &nbsp;+ O2 ——&gt; N2 + 2 H2O &nbsp; &nbsp; ΔH= -622 kJ</p><p>2 H2 + O2 ——&gt; 2 H2O &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;ΔH= -570 kJ</p><p>2 H2O2 &nbsp; &nbsp; ——&gt; &nbsp;2 H2 &nbsp;+ 2 O2 &nbsp; &nbsp; &nbsp;ΔH= 2× 188 kJ</p><p>______________________________________+</p><p>N2H4 + H2O2 ——&gt; N2 + 4 H2O &nbsp; &nbsp;ΔH= -816 kJ/mol</p><p>&nbsp;</p><p>Mr N2H4 = 32</p><p>N2H4: 6,4/32 = 0,2 mol</p><p>&nbsp;</p><p>ΔH_reaksi= 0,2 × -816&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; = -163,2 kJ</p>