tolong bantuin soal interval kak

<p>Untuk pertidaksamaan pertama:<br><br>7x - 1 ≤ 10x + 4</p><p>7x - 1 <strong>-10x </strong>≤ 10x + 4 <strong>-10x &nbsp; &nbsp;&nbsp;</strong><i>(kurangi 10x kedua ruas)</i></p><p>-3x -1 ≤ 4</p><p>-3x -1 <strong>+1 </strong>≤ 4 <strong>+1&nbsp;</strong> &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;<i> (tambah 1 kedua ruas)</i></p><p>-3x ≤ 5</p><p>-3x<strong>/-3</strong> ≤ 5<strong>/-3&nbsp;</strong> &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;<i>(bagi -3 kedua ruas, dan ganti simbolnya)</i></p><p>x ≥ -5/3</p><p>HP = {x I x ≥ -5/3, x∈R}</p><p>&nbsp;</p><p>Untuk pertidaksamaan kedua:</p><p>&nbsp;</p><p>-2 &lt; 1-5x ≤ 3</p><p>&nbsp;</p><p>Pertidaksamaan tersebut dapat dibagi menjadi dua interval, yaitu:</p><p>&nbsp;</p><p>a) -2 &lt; 1-5x</p><p>&nbsp; &nbsp; &nbsp;-2 <strong>+5x </strong>&lt; 1-5x <strong>+5x</strong> &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;<i> (tambah 5x kedua ruas)</i></p><p>&nbsp; &nbsp; &nbsp;-2+5x &lt; 1</p><p>&nbsp; &nbsp; &nbsp;-2+5x <strong>+2</strong> &lt; 1 <strong>+2</strong> &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;<i>(tambah 2 kedua ruas)</i></p><p>&nbsp; &nbsp; &nbsp; 5x &lt; 3</p><p>&nbsp; &nbsp; &nbsp; 5x<strong>/5</strong> &lt; 3<strong>/5</strong> &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;<i> &nbsp; &nbsp;(bagi 5 kedua ruas)</i></p><p><strong>&nbsp; &nbsp; &nbsp;&nbsp;</strong>x &lt; 3/5</p><p>&nbsp; &nbsp; &nbsp; x &lt; 0,6</p><p>&nbsp; &nbsp; &nbsp; HP₁= {x I x&lt;0,6 , x∈R}</p><p>&nbsp;</p><p>b) 1-5x ≤ 3</p><p>&nbsp; &nbsp; &nbsp;1-5x<strong> +5x</strong> ≤ 3 <strong>+5x</strong> &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;<i> &nbsp; (tambah 5x kedua ruas)</i></p><p><strong>&nbsp; &nbsp; &nbsp;</strong>1 ≤ 3+5x</p><p>&nbsp; &nbsp; &nbsp;1 <strong>-3 </strong>≤ 3+5x <strong>-3 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;</strong> &nbsp; &nbsp; &nbsp; &nbsp;&nbsp;<i>(kurang 3 kedua ruas)</i></p><p><strong>&nbsp; &nbsp; &nbsp;</strong>-2 ≤ 5x</p><p>&nbsp; &nbsp; &nbsp;5x ≥ -2</p><p>&nbsp; &nbsp; &nbsp;5x<strong>/5 </strong>≥ -2<strong>/5 &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;</strong><i><strong> </strong>(bagi 5 kedua ruas)</i></p><p><strong>&nbsp; &nbsp; &nbsp;</strong>x ≥ -0,4&nbsp;</p><p>&nbsp; &nbsp; &nbsp;HP₂= {x I x≥-0,4 , x∈R}</p><p>&nbsp;</p><p>Untuk menyelesaikan interval -2 &lt; 1-5x ≤ 3, iriskan himpunan penyelesaian interval pertama dengan kedua</p><p>&nbsp;</p><p>HP = HP₁∩ HP₂</p><p>&nbsp; &nbsp; &nbsp; &nbsp;= {x I x&lt;0,6 , x∈R} ∩ {x I x≥-0,4 , x∈R}&nbsp;</p><p>&nbsp; &nbsp; &nbsp; &nbsp;= {x I -0,4 ≤ x &lt; 0,6 , x∈R}&nbsp;</p>