Nabilah A
17 November 2023 02:18
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Nabilah A
17 November 2023 02:18
Pertanyaan
Tolong bantu jawab ya, terimakasih
Tolong bantu jawab ya, terimakasih
3
3
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Fauzan A
17 November 2023 06:58
<p>C. ∠BAD = 40°</p><p>∠BAD + ∠BCD = 180</p><p>∠BAD + 140 = 180</p><p>∠BAD = 40°</p><p> </p><p>D. ∠ABC = 105°</p><p>∠ABC + ∠ADC = 180</p><p>∠ABC + 75 = 180</p><p>∠ABC = 105°</p><p> </p><p>B. y = 15°</p><p>karena ∠BAD = 40</p><p>maka 3y - 5 = 40</p><p>3y - 5 = 40</p><p>3y = 45</p><p>y = 15°</p><p> </p><p>A. x = 51°</p><p>karena ∠ABC = 105</p><p>maka 2x + 3 = 105</p><p>2x + 3 = 105</p><p>2x = 102</p><p>x = 51°</p>
C. ∠BAD = 40°
∠BAD + ∠BCD = 180
∠BAD + 140 = 180
∠BAD = 40°
D. ∠ABC = 105°
∠ABC + ∠ADC = 180
∠ABC + 75 = 180
∠ABC = 105°
B. y = 15°
karena ∠BAD = 40
maka 3y - 5 = 40
3y - 5 = 40
3y = 45
y = 15°
A. x = 51°
karena ∠ABC = 105
maka 2x + 3 = 105
2x + 3 = 105
2x = 102
x = 51°
· 5.0 (3)
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H. Endah
Mahasiswa/Alumni Universitas Negeri Yogyakarta
17 November 2023 07:22
<p>Jawaban: </p><p>a. x = 51°</p><p>b. y = 15° </p><p>c. ∠BAD = 40°</p><p>b. ∠ABC = 105°</p><p> </p><p>Konsep:</p><p>Sifat segiempat tali busur lingkaran pada gambar di atas:</p><p>∠A + ∠C = 180° dan ∠B + ∠D = 180°</p><p> </p><p>Pembahasan:</p><p>∠ADC + ∠ABC = 180°</p><p>75° + 2x + 3 = 180°</p><p>2x + 78° = 180°</p><p>2x = 180° - 78°</p><p>2x = 102°</p><p>x = 102°/2</p><p>x = 51°</p><p> </p><p>∠BAD + ∠BCD = 180°</p><p>3y - 5 + 140° = 180°</p><p>3y + 135° = 180°</p><p>3y = 180° - 135°</p><p>3y = 45°</p><p>y = 45°/3</p><p>y = 15°</p><p> </p><p>∠BAD = 3y - 5</p><p>= 3(15°) - 5</p><p>= 45° - 5</p><p>= 40°</p><p> </p><p>∠ABC = 2x + 3</p><p>= 2(51°) + 3</p><p>= 102° + 3</p><p>= 105° </p><p> </p><p>Jadi, hasilnya:</p><p>a. x = 51°</p><p>b. y = 15° </p><p>c. ∠BAD = 40°</p><p>b. ∠ABC = 105°</p>
Jawaban:
a. x = 51°
b. y = 15°
c. ∠BAD = 40°
b. ∠ABC = 105°
Konsep:
Sifat segiempat tali busur lingkaran pada gambar di atas:
∠A + ∠C = 180° dan ∠B + ∠D = 180°
Pembahasan:
∠ADC + ∠ABC = 180°
75° + 2x + 3 = 180°
2x + 78° = 180°
2x = 180° - 78°
2x = 102°
x = 102°/2
x = 51°
∠BAD + ∠BCD = 180°
3y - 5 + 140° = 180°
3y + 135° = 180°
3y = 180° - 135°
3y = 45°
y = 45°/3
y = 15°
∠BAD = 3y - 5
= 3(15°) - 5
= 45° - 5
= 40°
∠ABC = 2x + 3
= 2(51°) + 3
= 102° + 3
= 105°
Jadi, hasilnya:
a. x = 51°
b. y = 15°
c. ∠BAD = 40°
b. ∠ABC = 105°
· 5.0 (1)
Sopyan K
18 November 2023 05:34
<p>B Nilai y</p>
B Nilai y
· 0.0 (0)
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